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creativ13 [48]
2 years ago
5

A field is to be fertilized at a cost of $0.06 per square yard. The rectangular part of the field is 85 yards long and the diame

ter of each semicircle is 49 yards. Find the cost of fertilizing the field. Use 3.14 for π.
Mathematics
1 answer:
ELEN [110]2 years ago
3 0
Need pictures please. WHat is the width of the yard?
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A direct variation function contains the points (–9, –3) and (–12, –4). Which equation represents the function?
Natasha_Volkova [10]
First, find the slope between the two points. 
Slope = y2-y1 / x2-x1
-4+3/ -12+9
-1/-3
1/3 is the slope of this equation. 
You do not have to go any further to find b or the y-intercept because it appears that b or the y-intercept is 0 in this case. 
y= 1/3x or in other words y= x/3
4 0
2 years ago
Read 2 more answers
Canteen A, canteen B and Canteen C repeat their lunch means every 12 days, 8days and 10 days respectively. All three canteens se
Katyanochek1 [597]

Answer:

120 days

Step-by-step explanation:

Canteen A = 12 days

Canteen B = 8 days

Canteen C = 10 days

How many days later will all three canteen serving noodles soup again?

To find the number of days all 3 canteens will serve food again, find the lowest common multiples of all 3 canteens

Canteen A = 12 days

34, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144

Canteen B = 8 days

16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120

Canteen C = 10 days

20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130

The lowest common multiple of 12 days, 8 days and 10 days is 120 days

The next day all 3 canteens will serve soup together again is the next 120 days

3 0
2 years ago
The​ life, in​ years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o
Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

\bf P(X

So, the probability that a switch fails in the first year is

\bf P(X

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and  

\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}

where  

\bf \binom{100}{k} equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999

3 0
2 years ago
What's the value of 6.8(98.44−84.29)+33.1??
soldi70 [24.7K]

Answer:

129.32

Step-by-step explanation:

You multiply 6.8 by both values in the parenthesis and then subtract that number and lastly, take that value and add it to 33.1 which equals 129.32

7 0
2 years ago
Read 2 more answers
Which of the following functions is graphed below?
dalvyx [7]

Answer:

The function graphed is y = Ix - 5I - 4 ⇒ answer D

Step-by-step explanation:

* Lets explain how to solve this problem

- From the graph

# The graph intersects the x-axis at x = 1 and x = 9

∴ The x-intercepts are 1 and 9

- We can find x-intercept by equate y by 0

* Lets equate the answers by zero to find the x-intercept

# y = Ix + 5I - 4

∵ Ix + 5I - 4 = 0

- Add 4 to both sides

∴ Ix + 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix + 5I = 4

∴ x + 5 = 4 ⇒ subtract 5 from both sides

∴ x = -1

- OR

∴ x + 5 = -4 ⇒ subtract 5 from both sides

∴ x = -9

∴ The x-intercepts are -1 and -9 not the same with figure

# y = Ix - 5I + 4

∵ Ix - 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix - 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix + 5I + 4

∵ Ix + 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix + 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix - 5I - 4

∵ Ix - 5I - 4 = 0

- Add 4 to both sides

∴ Ix - 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix - 5I = 4

∴ x - 5 = 4 ⇒ add 5 to both sides

∴ x = 9

- OR

∴ x - 5 = -4 ⇒ add 5 to both sides

∴ x = 1

∴ The x-intercepts are 1 and 9 the same with figure

* The function graphed is y = Ix - 5I - 4

5 0
2 years ago
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