The answer is 49.92%
Let's use the <span>Hardy-Weinberg principle:
p + q = 1
p</span>² + 2pq + q² = 1
<span>
where:
p - the frequency of dominant allele G
q - </span>the frequency of recessive allele g
p² - the frequency of homozygous dominant individuals GG with colour green
2pq - the frequency of heterozygous individuals Gg with colour green
p² - the frequency of homozygous recessive individuals gg with color brown
23% of the population is brown: p² = 23% = 0.23
p = √(p²) = √0.23 = 0.48
p = 0.48
p + q = 1
0.48 + q = 1
q = 1 - 0.48 = 0.52
<span>The percentage of the population that is expected to be heterozygous is 2pq:
2pq = 2 * p * q = 2 * 0.48 * 0.52 = 0.4992 = 49.92%</span>
I believe it's the long arm of chromosome 17.
<h2>Cytokinesis in animal cells</h2>
Explanation:
- The force for cytokinesis is generated by kinesin motors on microtubule bundles that form the contractile ring:This statement is false because cytokinesis in animal cells starts with the assembly of contractile ring,contractile band consists of actin and myosin(microfilaments) which catalyse cleavage furrow formation
- As the contractile ring constricts, its thickness increases to keep a constant volume:This statement is false because thickness remains constant
- The midbody forms from bundles of actin and myosin: This statement is false because contractile ring forms bundles of actin and myosin whereas midbody is formed from microtubules
- Local activation of Ran GTPase triggers the assembly and contraction of the contractile ring:This statement is false because local activation of Rho mediates profilin binding to actin and helps in assembly and contraction of contractile ring
The four letter string comes out to be FFFF
Yeah it haves to be C if not then it could be b I think but I probably more positive with c
