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marissa [1.9K]
2 years ago
4

The molar mass of aluminum oxide (Al2O3) is

Chemistry
1 answer:
Anuta_ua [19.1K]2 years ago
3 0

Answer:

\frac{1molAl_2O_3}{102.0gAl_2O_3}

Explanation:

Hello,

In this case, as the molar mass means that 1 mole of a substance has an specific amount of grams of the same substance, for aluminium oxide, we see that in one mole, there are 102.0 grams of it, which is symbolized by:

\frac{102.0gAl_2O_3}{1molAl_2O_3}

Nonetheless, the inverted molar mass, which is useful to compute the moles of aluminium oxide when mass is given is defined as:

\frac{1molAl_2O_3}{102.0gAl_2O_3}

Which has now moles above and grams below.

Best regards.

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A rigid, 28-L steam cooker is arranged with a pressure relief valve set to release vapor and maintain the pressure once the pres
MaRussiya [10]

Answer:

\Delta S_{source}>-1.204\frac{kJ}{K}

Explanation:

Hello!

In this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy:

s_1=s_{f,175kPa}+q*s_{fg,175kPa}\\\\s_1=1.4850\frac{kJ}{kg*K} +0.1*5.6865\frac{kJ}{kg*K}=2.0537\frac{kJ}{kg*K}

Now the entropy at the final state given the new 40-% quality:

s_2=s_{f,150kPa}+q*s_{fg,150kPa}\\\\s_2=1.4337\frac{kJ}{kg*K} +0.4*5.7894\frac{kJ}{kg*K}=3.7495\frac{kJ}{kg*K}

Next step is to compute the mass of steam given the specific volume of steam at 175 kPa and the 10% quality:

m_1=\frac{0.028m^3}{(0.001057+0.1*1.002643)\frac{m^3}{kg} } =0.274kg\\\\m_2=\frac{0.028m^3}{(0.001053+0.4*1.158347)\frac{m^3}{kg} } =0.0603kg

Then, we can write the entropy balance:

\Delta S_{source}+\frac{Q}{T_1} -\frac{Q}{T_2} +s_2m_2-s_1m_1-s_{fg}(m_2-m_1)>0

Whereas sfg stands for the entropy of the leaving steam to hold the pressure at 150 kPa and must be greater than 0; thus we plug in:

Which is such minimum entropy change of the heat-supplying source.

Best regards!

3 0
2 years ago
Which of the following descriptions best describes a weak base?
Westkost [7]

Answer:

umm.. B. a base that generates a lot of hydroxide ions in water.

5 0
2 years ago
1. Electronegativity is the… a. amount of energy required to remove the most loosely bound electron from an atom. b. tendency of
Kitty [74]

Answer: C.

ability of an atom to attract an electron from another atom toward itself.

Explanation:

Electronegativity is the chemical property that describes the ability of an atom to attract electron to itself. It is responsible for bond formation between atoms.

8 0
2 years ago
Read 2 more answers
What is the percent yield of this reaction if 22.o g of Mgl2 is produced by the reaction of 25.0 g of Mg with 25.0 g of l2?
expeople1 [14]

% yield = 80.719

<h3>Further explanation</h3>

Given

22.0 g of Mgl₂

25.0 g of Mg

25.0 g of l₂

Required

The percent yield

Solution

Reaction

Mg + I₂⇒ MgI₂

mol Mg = 25 g : 24.305 g/mol = 1.029

mol I₂ = 25 g : 253.809 g/mol = 0.098

Limiting reactant = I₂

Excess reactant = Mg

mol MgI₂ based on I₂, so mol MgI₂ = 0.098

Mass MgI₂ (theoretical):

= mol x MW

= 0.098 x 278.114

= 27.255 g

% yield = (actual/theoretical) x 100%

% yield = (22 / 27.255) x 100%

% yield = 80.719

8 0
1 year ago
Electroplating is a way to coat a complex metal object with a very thin (and hence inexpensive) layer of a precious metal, such
8_murik_8 [283]

Answer:

0.0164 g

Explanation:

Let's consider the reduction of silver (I) to silver that occurs in the cathode during the electroplating.

Ag⁺(aq) + 1 e⁻ → Ag(s)

We can establish the following relations.

  • 1 A = 1 C/s
  • The charge of 1 mole of electrons is 96,468 C (Faraday's constant)
  • 1 mole of Ag(s) is deposited when 1 mole of electrons circulate.
  • The molar mass of silver is 107.87 g/mol

The mass of silver deposited when a current of 0.770 A circulates during 19.0 seconds is:

19.0s \times \frac{0.770c}{s} \times \frac{1mole^{-} }{96,468C} \times \frac{1molAg}{1mole^{-}} \times \frac{107.87g}{1molAg} = 0.0164 g

5 0
2 years ago
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