You do not make any sense. can you restate your question please
Answer: Yes Rozonda's definition is valid
Step-by-step explanation:
Answer:
For k = 36, there is 0 solutions
For other values of k, there is 1
We never got infinite solutions on the system.
Step-by-step explanation:
We have 2 unknowns and 2 equations:
E1 8x1 + x2 = 18
E2 k*22 x1 + 9 x2 = 18
If we multiply the E1 by 9 we obtain
E3 72 x1 + 9x2 = 162
if we substract E3 with E2 we obtain
(72- 2k) x1 = 144
Thus,
x1 = 144/ (72-2k)
That is, if 72-2k = 0, otherwise there is no solution. And 72-2k = 0 when k = 72/2 = 36.
If k is not 36, then
x1 = 144/(72-2k) and we can replace this value to obtain x2 by using E1
x2 = 18-8x1 = 18- 8 * (144/72-2k)
Which is a specific number that depends only on k. Thus,
for k = 36, there is 0 solutions
for other values of k, there is unique solution.
Answer:
(1). y = x ~ Exp (1/3).
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
Step-by-step explanation:
Kindly check the attachment to aid in understanding the solution to the question.
So, from the question, we given the following parameters or information or data;
(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.
(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "
(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."
(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.
Recall the important identities:
i)

, the difference of squares formula.
ii)

, for any angle x.
Then,
from i)

then, from ii), we have

Answer: cos(theta)