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Kisachek [45]
2 years ago
15

kayla had 20 candies. kayla gave 1/5 of the candies to her sister. of the amount left 3/8 to her friend. how many candies does k

ayla have left for her self
Mathematics
2 answers:
Misha Larkins [42]2 years ago
5 0

Answer:

0 MUTHERFRUCKA!

bija089 [108]2 years ago
4 0

Answer:

10

Step-by-step explanation:

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Caitlin had used more thank 2 pounds of clay to make a jar? Would the amount remaining have been more or less than your answer t
11111nata11111 [884]
You do not make any sense. can you restate your question please

4 0
2 years ago
Rozonda defines the diameter of a circle as a line segment passing through the center of the circle. Is Rozonda’s definition val
larisa [96]

Answer: Yes Rozonda's definition is valid

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
For which values of k does the system of linear equations have zero, one, or an infinite number of solutions? [Note: not all thr
anastassius [24]

Answer:

For k = 36, there is 0 solutions

For other values of k, there is 1

We never got infinite solutions on the system.

Step-by-step explanation:

We have 2 unknowns and 2 equations:

E1     8x1 + x2 = 18

E2    k*22 x1 + 9 x2 = 18

If we multiply the E1 by 9 we obtain

E3     72 x1 + 9x2 = 162

if we substract E3 with E2 we obtain

(72- 2k) x1 = 144

Thus,

x1 = 144/ (72-2k)

That is, if 72-2k = 0, otherwise there is no solution. And 72-2k = 0 when k = 72/2 = 36.

If k is not 36, then

x1 = 144/(72-2k) and we can replace this value to obtain x2 by using E1

x2 = 18-8x1 = 18- 8 * (144/72-2k)

Which is a specific number that depends only on k. Thus,

for k = 36, there is 0 solutions

for other values of k, there is unique solution.

4 0
2 years ago
An attempt to establish a video call via some social media app may fail with probability 0.1. If connection is established and i
xxMikexx [17]

Answer:

(1). y = x ~ Exp (1/3).

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

Step-by-step explanation:

Kindly check the attachment to aid in understanding the solution to the question.

So, from the question, we given the following parameters or information or data;

(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.

(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "

(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."

(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.

8 0
2 years ago
Simplify square root of (1-sin theta)(1+sin theta)
Vinil7 [7]
Recall the important identities:

i) (a-b)(a+b)= a^{2}- b^{2}, the difference of squares formula.

ii) sin^{2} x+cos^{2}x=1, for any angle x.

Then,

from i)

\sqrt{(1-sin(theta))(1+sin(theta))}= \sqrt{1- sin^{2}(theta) }

then, from ii), we have 

\sqrt{1- sin^{2}(theta) }= \sqrt{cos^{2}(theta) }=cos(theta)


Answer: cos(theta) 

6 0
2 years ago
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