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Nataly_w [17]
2 years ago
12

The two-way table of column relative frequencies below shows data on whether or not a person has internet access and their prefe

rred method to communicate with friends.
Based on the data, which of the following statements must be true?

(Choice A)
A person who prefers to communicate with friends in person is more likely to have no internet access than to have internet access.

(Choice B)
A person with internet access is more likely than a person without internet access to prefer the wired telephone to communicate with their friends.

(Choice C)
A person with internet access is more likely than a person without internet access to prefer text messaging to communicate with their friends.

(Choice D)
More people without internet access prefer using social networking than people with internet access.

Mathematics
1 answer:
BabaBlast [244]2 years ago
6 0

Answer: c

Step-by-step explanation: 54% of people with internet access prefer text messaging, while only 31% of people without internet access prefer text messaging.

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It is 141.4 centimetres. This is because the circumference is obtained by multiplying pi with the diameter.
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1).He gastado 5/8 de mi dinero. Si en lugar de gastar los 5/8 hubiera gastado los 2/5 de mi dinero, tendria ahora 72 soles mas d
TiliK225 [7]

Answer:

1. The amount that was not spent is: 1080 soles

2. The answer is 5.

Step-by-step explanation:

Question 1. There are two situations:

If you spent 5/8 of the money then notice, that u did not spend 3/8.

If you spend 2/5 of the money, then you would have 72 more.

So think, this equation:

3/8x + 72 = 2/5x

2/5 of the money is the value for what you did not spend plus 72, the amount you would have, where x is the answer for the total of money.

72 = 2/5x - 3/8x

72 = 1/40x

x = 2880 soles

As you did not spend 3/8 of 2880, the answer is 1080 soles

Notice that if u spent 2/5 of 2880, you would have 1152 soles, so, the 1080 + 72, as the problem said.

Question 2.

We think letters for this excersise.

N = My born year

2020 (this year) - N = E (my age, now)

So N + 10 = when I get 10 years old

N + 20 = when I get 20 years old

N + 30 = when I get 30 years old

N + 40 = when I get 40 years old

The problem says:

(N+10) + (N+20) - (N+E) = 2020

((N+30)+E) - (N-40) = X  

So if 2020 - N = E, then notice that 2020 - E = N. Let's replace this in the equation form:

((2020-E)+10) + ((2020-E)+20) - ((2020-E)+E) = 2020

No minus in the first two terms, so we can break the ( )

2020-E+10 + 2020-E+20 - ((2020-E)+E) = 2020

We apply the distributive property for the second term

2020-E+10 + 2020-E+20 - 2020+E-E = 2020

We can cancel two E, and the 2020, so the new form will be:

2020 - 2E + 30 = 2020

We can also cancel the 2020, so if we reorder the equation, we have:

-2E = -30

E = 15 That's my age, so my born's year is 2020 - 15 = 2005 (N)

Look:

(2005 + 10) + (2005+20) - (2005+15) = 2020

So now, the last part

((2005+30)+15) - (2005+40) = 5

3 0
1 year ago
A metal disc of 12cm in diameter and 5cm thick is melted down and cast into a cylindrical bar of diameter 5cm .How long is the b
Trava [24]

Answer:

d bar

Step-by-step explanation:

3 0
2 years ago
A school replaced 20% of it computers with new ones . what the total number of computers in the school if 55 computers were repl
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The total is 275 because 100% divided by 20% is 5 and if 20%= 55 then that means that 55 goes into 100% 5 times so you multiply 55 by 5 to get 275. Hope I helped! Please rate me as the brainliest!
7 0
2 years ago
The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
Andru [333]

Answer:

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Step-by-step explanation:

Values (x) ∑(Xi-X)^2

----------------------------------

29.1                    0.1702

28.5                  1.0252

28.8                  0.5077

29.4                   0.0127

29.8                  0.0827

29.8                  0.0827

30.1                   0.3452

30.6                   1.1827

----------------------------------------

236.1                 3.4088

Mean = 236.1 / 8 = 29.51

S_{x}=\sqrt{3.4088/(8-1)}=0.6978

Statement of the null hypothesis:

H0: u ≥ 30 the mean wedding cost is not less than $30,000

H1: u < 30 the mean wedding cost is less than $30,000

Test Statistic:

t=\frac{X-u}{S/\sqrt{n}}=\frac{29.51-30}{0.6978/\sqrt{8}}= \frac{-0.49}{0.2467}=-1.9861

Test criteria:

SIgnificance level = 0.05

Degrees of freedom = df = n - 1 = 8 - 1 = 7

Reject null hypothesis (H0) if

t

Finding in the t distribution table α=0.05 with df=7, we have

t_{0.05,7}=2.365

t>-t_{0.05,7} = -1.9861 > -2.365

Result: Fail to reject null hypothesis

Conclusion: Do no reject the null hypothesis

u ≥ 30 the mean wedding cost is not less than $30,000

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Hope this helps!

5 0
2 years ago
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