The two-way table of column relative frequencies below shows data on whether or not a person has internet access and their prefe
rred method to communicate with friends.
Based on the data, which of the following statements must be true?
(Choice A)
A person who prefers to communicate with friends in person is more likely to have no internet access than to have internet access.
(Choice B)
A person with internet access is more likely than a person without internet access to prefer the wired telephone to communicate with their friends.
(Choice C)
A person with internet access is more likely than a person without internet access to prefer text messaging to communicate with their friends.
(Choice D)
More people without internet access prefer using social networking than people with internet access.
Based on the data, which of the following statements must be true?
(Choice A)
A person who prefers to communicate with friends in person is more likely to have no internet access than to have internet access.
(Choice B)
A person with internet access is more likely than a person without internet access to prefer the wired telephone to communicate with their friends.
(Choice C)
A person with internet access is more likely than a person without internet access to prefer text messaging to communicate with their friends.
(Choice D)
More people without internet access prefer using social networking than people with internet access.
1 answer:
You might be interested in
Answer:
Probability that Adam and Ella will be selected:
Step-by-step explanation:
Probabilities
The probability of a random event E to occur is a real number between 0 and 1, both inclusive, where 0 indicates an impossible event and 1 a sure event. There are many techniques to compute probabilities depending on the particular situation and distribution.
This question will be solved by simple calculations and logic, given its simplicity. We know the middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two of them are going to be selected at random to participate in the county chess tournament. We can calculate the number of different ways it can be done without any restriction. It's called the sample space.
The sample space of this event is the combination of 5 members regardless of their position. If {a,b,c,d,e} are the five members, then the possible combinations are {ab,ac,ad,ae,bc,bd,be,cd,ce,de}. Notice that there are only 10 possibilities because the combination ab is the same as ba since it's the same team for the tournament.
We can see there is only one combination of two specific letters out of 10. If a=Adam and e=Ella, only one combination is ae, the other 9 don't include both members, so the probability is
Answer:
Step-by-step explanation:
Using Pythagoras theorem , since it is a right angled triangle ,
side 1 = 10cm
side 2 = x cm
side 3 = x cm
Pythagoras theorem states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides. That is
100 =
divide through by 2 , we have
50 =
find the square root of both sides