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Ilia_Sergeevich [38]
2 years ago
5

The lateral area of a cone is 555 pi cm^2. The radius is 37 cm. What is the slant height to the nearest tenth of a centimeter?

Mathematics
2 answers:
andre [41]2 years ago
7 0

Answer:

Slant height = 15

Step-by-step explanation:

Well the lateral area of a cone is equal to πrl, where r = radius and l = slant height. So if the radius is 37, you will have the equation:

37π * l = 555π

Start by crossing out π

37 * l = 555

l = 15

This might be wrong since it is so clean, and the question asks to simplify.

sammy [17]2 years ago
5 0

Answer:

i would help you if i could but im sorry i dont know

Step-by-step explanation:

hgvfcgvhbutfugcj6fyjhvn,

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A vehicle travels 250 feet every three seconds find the value of the ratio the unit rate and the constant of proportionality how
PSYCHO15rus [73]

to find the unit rate/constant of proportionality , you'd have to dive 250 by three. and they are related because they are the same thing.

8 0
1 year ago
A. If a spacecraft was parked on Venus and needed to make a flight to Jupiter, how far would it need to travel? Show your work a
bija089 [108]
A. (Assume both planets are aligned with the sun and are on the same side of the sun.) Show your work and provide your answer in scientific notation. Jupiter = 778,500,000 km from sun. Venus = 108,200,000 km from sun.

778,500,000 – 108,200,000 = 670,300,000
It would need to travel 670,300,000 km/ 6.703 x 10 with a 8 squared km (as shown below)
10 {}^{8}


B.Mercury, Venus, and Earth are the three planets closest to the sun. Would their combined distance from the sun be greater or less than the distance from the sun to Neptune? Show your work and justify your answer. Mercury = 57,909,000 km Venus = 108,200,000 km Earth = 149,600,000 km 57,909,000 + 108,200,000 + 149,600,000 = 315,709,000 Less because 315,709,000 km is less than 4,498,000,000 km

C.If Earth was 10 times farther away from the sun than it is now, which planet would it be closest to? (Assume all the planets are aligned with the sun and are on the same side of the sun.) Compare Earth's new distance to that planet. How far apart would they be in standard notation? How far apart in scientific notation? Show your work. Earth = 149,600,000 km 149,600,000 x 10 = 1,496,000,000 Earth’s new distance = 1,496,000,000 Earth would be closest to Saturn. 1,496,000,000 – 1,429,000,000 = 67,000,000
They would be 67,000,000 km apart
Scientific notation: 6.7 x 10 with a 7 squared km (sorry I can't write this to show this figure but see below as you should write it exactly like how I typed it below followed by km)
10 {}^{7}


D. The space shuttle travels at about 28,000 km per hour. Using that information, estimate how many hours it will take the shuttle to reach Saturn from Earth. (Assume both planets are aligned with the sun and are on the same side of the sun.) Show your work. Convert your answer into scientific notation if necessary. Earth = 149,600,000 km
Saturn = 1,429,000,000 km
1,429,000,000 - 149,600,000 = 1,279,400,000
1,279,400,000 km
1,279,400,000 ÷ 28,000 = 45,692.8
Estimated hours it will take the shuttle to reach Saturn from Earth = 45,693
Scientific notation: 4.5693 x 10 with a 4 squared
(same with this one, it should be written as I have it shown below instead of how I first tried to explain it.)
10 {}^{4}






4 0
2 years ago
Levi bought 14 chicken wings for $22.40 how much would it cost for 12 wings
777dan777 [17]

Answer:

x =19.20

Step-by-step explanation:

We can use ratios to solve

14 wings      12 wings

------------- = ---------------

22.40          x

Using cross products

14x = 22.40 * 12

14x =268.8

Divide each side by 14

14x/14 = 268.8/14

x =19.20

8 0
1 year ago
Read 2 more answers
In preparing for holiday festivities, confetti is stuffed into decorative spherical containers. Each container has a diameter of
professor190 [17]

Answer:

C. 905 in³

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, sphere

We know that the volume of a sphere is expresses as

V= 4/3πr³

Given that the diameter of the sphere is 12inches

Radius r= 12/2= 6 inches

Substituting our radius we can solve for the volume

V=4/3(3.142*6³)

V= (4*3.142*216)/3

V= 2714.68/3

V= 904.9in³

Approximately V= 905in³

5 0
1 year ago
Which identity could be the missing step to verify the identity (cos theta)(csc theta)=cot theta
N76 [4]
(cosx)(cscx) = cotx
cscx = 1/sinx
(cosx)(1/sinx) = (cosx/sinx)
cosx/sinx = cotx

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5 0
1 year ago
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