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Irina18 [472]
2 years ago
15

Ying Zyiyu covered the first 300 miles of a trip going at 60 mph and the last hundred going at 40 mph. What was his average spee

d for the entire trip?
NEED IN 5 MINUTES
Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
5 0

Answer:

Average speed is (total distance)/(total time).

To find the total time we need to do some division.

Time for 200 miles=200/50=4 hours.

Time for 100=100/40=5/2 hours.

Total time=13/2 hours. Total distance=200+100=300 miles.

Av speed=300/(13/2)=300×2/13=600/13=46.15 mph approx.

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What’s 8/15 divided by 4/5
iragen [17]

Answer: 2/3

Step-by-step explanation: In this problem, we have 8/15 ÷ 4/5. Dividing by a fraction is the same as multiplying by its reciprocal. In other words, we can change the division sign to multiplication and flip the second fraction.

8/15 ÷ 4/5 can be rewritten as 8/15 × 5/4

Now, we are simply multiplying fractions so we multiply across the numerators and multiply across the denominators.

8/15 × 5/4 = 40/60 = 2/3

8 0
2 years ago
In a survey, a group of students were asked to name their favorite elective class. There were 15 students who chose “other." How
lyudmila [28]

Answer:

50 % of them participated

7 0
2 years ago
Find the volume of a right circular cone that has a height of 5.9 in and a base with a diameter of 11.2 in. Round your answer to
schepotkina [342]

Answer:

Step-by-step explanation:

volume=1/3×πr²h

=1/3π×(11.2/2)²×5.9

=1/3×22/7×(5.6)²×5.9

≈1/3×22×5.6×8×5.9

≈1938.3 in³

6 0
2 years ago
Please help me :(
Tanzania [10]

We can solve this problem by correctly analyzing the location of the points.

If the center of rotation is a point outside the triangle, then this would mean that there would be quadrant shift (revolution) of the whole triangle itself. Hence this would mean that the resulting triangle will not touch the pre-image at any point at all.

If the center of rotation is a point on the perimeter of the triangle, this would also result in a quadrant shift (revolution) or movement of the triangle.

Now if the center of rotation is a point inside the triangle, then this would be a simple rotation on its own quadrant hence the resulting image will touch the pre-image at more than one point. Hence the correct points are:

<span>point D and point E</span>

8 0
2 years ago
Suppose that on a certain examination in advanced mathematics, students from univer sity A achieve scores that are normally dist
harkovskaia [24]

Answer:

P(z>-1.768)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the scores for the univerisity A, and we know that:

X \sim N (\mu = 625,\sigma =\sqrt{100}= 10)

Let Y the scores for the univerisity B, and we know that:

Y \sim N (\mu = 600,\sigma =\sqrt{150}= 12.25)

We select a sample size of size n=2, and since the distirbution for X is normal then the distribution for the sample mean would be given by:

\bar X \sim N(\mu=625, \frac{\sigma}{\sqrt{n}}=\frac{10}{\sqrt{2}}=7.07)

And for the univeristy B we select a sample of n=3

\bar Y \sim N(\mu=600, \frac{\sigma}{\sqrt{n}}=\frac{12.25}{\sqrt{3}}=7.07)

Since both sample means are normally distributed then the difference Z= \bar X- \bar Y is also normal distributed with the following parameters:

Z= \bar X -\bar Y \sim N(\mu_Z=625-600=25, \sigma_z= \sqrt{100+100}=14.14)

And we want this probability:

P(Z>0)

And we can use the z score given by:

Z= \frac{z -\mu_z}{\sigma_z}

And if we replace we got :

Z= \frac{0-25}{14.14}=-1.768

And if we find the probability using the normla standard table or excel we got:

P(z>1.768) =1-P(Z

3 0
2 years ago
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