Answer:
see explaination
Step-by-step explanation:
Here the null hypothesis is that the PCB survives against the alternate that the PCB 'does not survive'. The test says that the PCB will survice if it is classified as 'good'; or, it will not survive if it is classifies as 'bad'.
a. The Type II error is the error committed when a PCB which cannot actually survive is classified as 'good'.
b. Therefore P(Type II error) = P(The PCB is classified as 'good' | PCB does not survives) = 0.03.
11/56 inches or 0.196 inches must be removed.
The pipe measures 4/7 inches but needs to be reduced to 3/8 inches.
In order to find out the inches to be removed, you must subtract the length that the pipe should be from the length that it currently is.
<em>Length to be removed = 4/7 - 3/8</em>
You need a common denominator so find the lowest common factor of both denominators:
= 56
In the shared fraction, multiply the numerator by the number you get when you divide 56 by the denominator.
= 56/7 = 8 8 x 4 = 32
= 56 / 8 = 7 7 x 3 = 21
= (32 - 21) / 56
= 11 / 56 inches
= 0.196 inches
In conclusion, 11/56 inches must be removed to get the pipe to 3/8 inches
<em>Find out more at brainly.com/question/4681199.</em>
Point W because the line intersects the y axis at W (0,2). sorry if it’s wrong :/
Answer:
(i) It represents change in expenditure by candidates A; (ii) 
Step-by-step explanation:
