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iren2701 [21]
2 years ago
7

A bag contains eleven equally sized marbles, which are numbered. Two marbles are chosen at random and replaced after each select

ion.
Eleven numbered marbles are shown. Marbles 2, 5, 6, 7, 8, 10, 11 are white. Marbles 1, 3, 4, 9 are purple.

What is the probability that the first marble chosen is shaded and the second marble chosen is labeled with an odd number?

StartFraction 10 Over 121 EndFraction
StartFraction 24 Over 121 EndFraction
StartFraction 6 Over 11 EndFraction
StartFraction 10 Over 11 EndFraction
Mathematics
2 answers:
prohojiy [21]2 years ago
6 0

EndFraction

StartFraction 24 Over 121 EndFraction

StartFraction 6 Over 11 EndFraction

StartFraction 10 Over 11 EndFraction

Karo-lina-s [1.5K]2 years ago
6 0

Answer:

StartFraction 24 Over 121 EndFraction

Step-by-step explanation:

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Driving across country, mike drove for 3 hours at a certain rate and for 4 hours at a rate 10 mph faster. If his total distance
Agata [3.3K]

Answer:

65 mph

Step-by-step explanation:

Let x mph be Mike's slower rate, then his faster rate is x+10 mph.

1. Mike drove for 3 hours at a slower rate, thus he drove

x\cdot 3=3x\ miles

2. Mike drove for 4 hours ar a faster rate, so he drove

(x+10)\cdot 4=4x+40\ miles

3. In total he drove 495 miles. Hence

3x+4x+40=495\\ \\7x=495-40\\ \\7x=455\\ \\x=65\ mph

5 0
2 years ago
Declare a structure whose tag name is point2d and that contains exactly two fields (or members, both of type double . the first
Varvara68 [4.7K]

In the C language, a structure is declared as follows :

 

struct <tag name> {

<span>     <1st member type> <1st member name></span>

<span>     <2nd member type> <2nd member name></span>

<span>      …..</span>

<span>     <nth member type> <nth member name></span>

};

 

Thus, a structure whose tag name is point2d that contains x and y, both double, is :

 

struct point2d {

<span>    double x;</span>

<span>    double y;</span>

<span>};</span>

4 0
2 years ago
The water pressure on Mustafa as he dives is increasing at a rate of 0.9920.9920, point, 992 atmospheres (\text{atm})(atm)left p
Paha777 [63]
This problem is a simple dimensional analysis. We are simply tasked to express the rate 0.992 atm/m to atm/km.

Dimensional analysis, in simpler terms, is just the process of expressing an answer in another unit by multiplying conversion factors.

For this problem, we'll need to perform the following:

\frac{0.992 atm}{m}= \frac{1000m}{1km} = \frac{992atm}{km}

Notice that we used the conversion factor 1000 meters = 1 kilometer to convert the units from atm/m to atm/km. Thus, we arrive at the final answer 992 atm/km.
8 0
2 years ago
Read 2 more answers
Tim Has M Dollars. Rebecca has $6 less than 1/10 Times The Number Of Dollars That Tim Has. Which Expression represents the total
Mrac [35]
M = Tim's dollar amount
R = Rebecca's dollar amount
MR = Tim and Rebecca's dollars together

R = (M x 1/10) - 6

MR = M + ((M x 1/10) - 6)

MR = 70 + ((70 x 1/10) - 6)

MR = 70 + (7 - 6)

MR = 70 + 1

MR = 71




8 0
2 years ago
Read 2 more answers
Consider the following problem: A farmer with 950 ft of fencing wants to enclose a rectangular area and then divide it into four
Alina [70]

Answer:

Step-by-step explanation:

(a)

Suppose we came up with an ideology whereby we pick a value for the length including the length dividing the inside into 4 parts(5 parallel sides), then we can get the value for breath by using the following process.

Let assume the length of the rectangle is 50;

Then, the breath can be calculated as follows:

= 50 × 5 = 250   ( since the breath is divided into 5 parallel sides)

The fencing is said to be 950 ft

So, 950 - 250 = 700

Then divided by 2, we get:

= 700/2

= 350

So for the first diagram; the length = 50 and the breath = 350

The area = 50 × 350 = 17500 ft²

Now, let's go up a little bit.

If the length increase to 100;

Then 100 × 5 = 500

⇒ 950 - 500 = 450

⇒ 450/2 = 225

The area = 225 × 100 = 22500 ft²

Suppose the length increases to 150

Then 150 × 5 = 750

⇒ 950 - 750 = 200

⇒ 200/2 = 100

The area = 150 × 100 = 15000 ft²

The diagrams for each of the outline above can be seen in the image attached below.

(b) The diagram illustrating the general solution can be seen in the second image provided below.

(c) The expression for  the total area A in terms of both x and y is:

Area A = x×y

(d) Recall that:

The fencing is said to be 950 ft.

And the length is divided inside into 5 parallel sides;

Then:

5x + 2y = 950  (from the illustration in the second image below)

2y  = 950 - 5x

y = \dfrac{950}{2} - \dfrac{5}{2}x

y = 475- \dfrac{5}{2}x

(e)

From (c); replace the value of y in (d) into (c)

Then:

Area A = x×y

f(x)= x\times ( 475 -\dfrac{5}{2}x)

Open brackets

f(x)= ( 475 x-\dfrac{5}{2}x^2)

(f)

By differentiating what we have in (e)

f(x)= ( 475 x-\dfrac{5}{2}x^2)

f'(x)= ( 475 (1)-\dfrac{5}{2}(2x))

f'(x)= 475 -5x

\implies  475 = 5x

x = 475/5

x = 95

From (d):

y = 475- \dfrac{5}{2}x

y = 475- \dfrac{5}{2}(95)

y =237.5

∴

Area A = x × y

Area A = 95 × 237.5

Area A = 22562.5 ft²

5 0
2 years ago
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