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Ronch [10]
2 years ago
5

The distance between Cincinnati, Ohio, and charlotte, North Carolina, is about 336 miles.The distance between Cincinnati and Chi

cago, Illinois, is about 247 miles. If Perry drove from charlotte to Chicago by way of Cincinnati, find the distance he drove.
Mathematics
1 answer:
bija089 [108]2 years ago
8 0
Cincinnati Ohio à<span> Charlote North CA = a total of 336 miles
Cincinnati </span>à<span> Chicago Illinois = a total of 247 miles
Perry drove from Charlote to Chicago by passing Cincinati. Find the distance she drove.
=> Note that the distance from charlotte to Cincinnati is 365 then from Cincinnati to Chicago is 247
=> 336 miles + 247 Miles
=> 583 miles
Penny drove for a total of 583 miles from Charlotte to Cincinnati to Chicago.

</span>



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Lin counts 5 bacteria under a microscope. She counts them again each day for four days, and finds
svetlana [45]

Answer:

Yes, but it is not linear. It is exponential :  f(x) = 5\cdot 2^{x-1}

Step-by-step explanation:

On the first day we have 5 bacteria.

On the second day we will have 5*2 = 10 bacteria.

On the third day we will have 10*2 = 5*2*2 = 5*2^2 = 20 bacteria.

On the fourth day we will have 20*2 = 5*2*2*2 = 5*2^3 = 40 bacteria.

We can see that

                                                f(x) = 5\cdot 2^{x-1},

where x is a number of days and f(x) gives us the number of bacteria.

4 0
1 year ago
Determine the value of $a$. [asy] pair w=(0,4); pair x=(0,0); pair y=(4,0); pair z=y+7/sqrt(2)*(1,1); dot(w); dot(x); dot(y); do
grandymaker [24]

Answer:

a=7

Step-by-step explanation:

The image is rendered and attached below.

Triangle WXY is an Isosceles right triangle, since WX=XY.

First, we determine the length of WY using Pythagoras Theorem.

WY=\sqrt{4^2+4^2}\\WY=\sqrt{32}

Since triangle WXY is Isosceles, \angle XYW=45^\circ

\angle XYZ=\angle XYW+\angle WYZ\\135^\circ=45^\circ+\angle WYZ\\\angle WYZ=135^\circ-45^\circ=90^\circ

Therefore:

Triangle WYZ is a right triangle with WZ as the hypothenuse.

Applying Pythagoras Theorem

WZ^2=WY^2+YZ^2\\9^2=(\sqrt{32})^2+a^2\\a^2=81-32\\a^2=49\\a^2=7^2\\$Therefore: a=7

3 0
2 years ago
Including Jose, there are eight people in his family.
SIZIF [17.4K]

Answer:

840

Step-by-step explanation:

Since the order matters, we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

The first seat is Jose's.

The remaining four are organized among the other 7 members. So

P_{(7,4)} = \frac{7!}{(7-4)!} = 840

So the correct answer is:

840

7 0
2 years ago
Read 2 more answers
Triangle J K L is shown. Angle K J L is 58 degrees and angle J L K is 38 degrees. The length of J K is 2.3 and the length of J L
Romashka-Z-Leto [24]
Try 3.7 and see it u got it
5 0
2 years ago
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Melissa wants to make a table representing the area of her vegetable garden for a variety of different lengths of the tomato pat
Ksenya-84 [330]

Answer:

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

Step-by-step explanation:

The date from the given table, is expressed as follows;

Area of Vegetable Garden (in square feet); 338, ___, 147.25, ___

Length of Tomato Patch (in feet); ___, 6.5, ___, 7

The length of the tomato patch increases with decrease in the area of the garden

Given that the length of the tomato patch is the independent variable, we can have;

Length of Tomato Patch (in feet); 6.25, 6.5, 6.75, 7

Therefore, for an increase in the length of the tomato patch from 6.25 to 6.75, (a change of Δl = 0.5) the area of the vegetable garden decreased from 338 to 147.25 which is a decrease of ΔA = 190.75

Therefore, the width of the tomato patch, w = ΔA/Δl = 190.75/0.5 = 381.5

The width of the tomato patch, w = 381.5 ft.

The relationship between the total area, TA, the area of the vegetable garden, <em>A</em>, and the length of the tomato patch, <em>l</em>, is therefore, given as follows;

A = TA - 381.5·l

338 = TA - 381.5×6.25

TA = 338 + 381.5×6.25 = 2,722.375

Therefore, when l = 6.5, we get

A = 2,722.375 - 381.5×6.5 = 242.625

When l = 7, we get

A = 2,722.375 - 381.5×7 = 51.875

Therefore, we get;

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

5 0
1 year ago
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