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2 years ago

Which number line model represents the expression 2.5+4.52.5+4.52, point, 5, plus, 4, point, 5?

Mathematics

1 answer:

cricket20 [7]2 years ago

6 0

Answer:

Check Explanation

Step-by-step explanation:

The number line models to pick from aren't attached to the question, So, I will draw and present the number line representing the addition of 2.5 to 4.5 in the attached image to this answer.

2.5 + 4.5 = 7.0

Hope this Helps!!!

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Solve for x: the quantity x plus fifty all over two equals thirteen times x

dusya [7]

Answer:

x = 2

Step-by-step explanation:

(x + 50)/2 = 13x, first multiply both sides by 2

x + 50 = 26x, next subtract x from both sides

50 = 25x, finally divide both sides by 25

2 = x

3 0

2 years ago

Read 2 more answers

For flights from a particular airport in January, there is a 30 percent chance of a flight being delayed because of icy weather.

lyudmila [28]

Answer:

0.335

Step-by-step explanation:

1. There is a 30 percent chance of a flight being delayed because of icy weather ,then the probability of being delayed is 0.3 and of being not delayed is 0.7.

2. If a flight is delayed because of icy weather, there is a 10 percent chance the flight will also be delayed because of a mechanical problem, then the probability of being delayed is 0.1 and the probabilty of not being delayed is 0.9.

3. If a flight is not delayed because of icy weather, there is a 5 percent chance that it will be delayed because of a mechanical problem (MP), then the probability of being delayed is 0.05 and the probabilty of not being delayed is 0.95. (See attached probability tree)

Delayed of icy weather - 0.3

Delayed of MP when weather is not icy - 0.7·0.05=0.035

Now, if one flight is selected at random from the airport in January, the probability that the flight selected will have at least one of the two types of delays is

0.3+0.035=0.335

8 0

2 years ago

Coordinates, gradient and tangent work (see image).

Ivenika [448]

Answer:

a) $P(x,2x^2-5),\ Q(x+h,2(x+h)^2-5)$

b) $4x+2h$

c) $4x$

Step-by-step explanation:

Given the curve

$y=2x^2-5$

a) If the x-coordinate of P is $x$ , then the y-coordinate is $2x^2-5,$ so point P has coordinates $(x,2x^2-5)$

If the x-coordinate of Q is $x+h$ , then the y-coordinate is $2(x+h)^2-5$ so point Q has coordinates $(x+h,2(x+h)^2-5)$

b) The gradient of the secant RQ is

$\dfrac{y_Q-y_P}{x_Q-x_P}\\ \\=\dfrac{(2(x+h)^2-5)-(2x^2-5)}{(x+h)-x}\\ \\=\dfrac{2(x+h)^2-5-x^2+5}{x+h-x}\\ \\=\dfrac{2(x+h)^2-2x^2}{h}\\ \\=\dfrac{2x^2+4xh+2h^2-2x^2}{h}\\ \\=\dfrac{4xh+2h^2}{h}\\ \\=4x+2h$