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Nesterboy [21]
2 years ago
14

Suppose an automobile manufacturer designed a radically new lightweight engine and wants to recommend the grade of gasoline that

will have the best fuel economy. The four grades are regular, economy, premium, and super premium. The test car made three trial runs on the test track using each of the four grades. The miles per gallon were recorded for each grade. At the 0.05 level, what is the critical value of F used to test the hypothesis that the miles per gallon for each fuel are the same? Kilometers per Liter Regular Economy Premium Super Premium 39.31 36.69 38.99 40.04 39.87 40.00 40.02 39.89 39.87 41.01 39.99 39.93
Mathematics
1 answer:
lapo4ka [179]2 years ago
4 0

Answer:

this is very confusing to understand that you want.

Step-by-step explanation:

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The box plots compare the number of students in Mr. Ishimoto’s classes and in Ms. Castillo’s classes over the last two semesters
Ilya [14]
<span>-Both box plots show the same interquartile range.
 >Interquartile range (IQR) is computed by Q3-Q1. 
For Mr. Ishimoto's class, Q3 is 35 and Q1 is 31. 35-31 = 4.
For Ms. Castillo's class, Q3 is 34 and Q1 is 30. 34-30 = 4.

</span><span>-Mr. Ishimoto had the class with the greatest number of students.
 >Mr. Ishimoto had 40 students, represented by the last data point of the whiskers.

</span><span>-The smallest class size was 24 students.
 >Which was Ms. Castillo's class.</span>
7 0
2 years ago
Read 2 more answers
Circle M has a radius of 7.0 cm. The shortest distance between P and Q on the
Lorico [155]

Answer:

oops sorry accidental click i don't know how to get out sorry for letting you down

Step-by-step explanation:

7 0
2 years ago
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A psychologist is collecting data on the time it takes to learn a certain task. For 50 randomly selected adult subjects, the sam
tatuchka [14]

Answer: (15.263,\ 17.537)

Step-by-step explanation:

According to the given information, we have

Sample size : n= 50

\overline{x}=16.40

s=4.00

Since population standard deviation is unknown, so we use t-test.

Critical value for  95 percent confidence interval  :

t_{n-1,\alpha/2}=t_{49, 0.025}= 2.009575\approx2.010

Confidence interval : \overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}

16.40\pm (2.010)\dfrac{4}{\sqrt{50}}\\\\=16.40\pm1.13702770415\\\\=16.40\pm1.1370\\\\=(16.40-1.1370,\ 16.40+1.1370)\\\\=(15.263,\ 17.537)

Required 95% confidence interval :  (15.263,\ 17.537)

8 0
2 years ago
Find the average value of the function i = 15(1 - e1/2t) from t = 0 to t = 4. A. 7.5(1 + e-2) B. 7.5(2 - e-2) C. 7.5(2 + e-2) D.
klasskru [66]
I think the average value of the function i = 15(1 - e1/2t) from t = 0 to t = 4 is <span>C. 7.5(2 + e-2). The correct answer is letter C.</span>
7 0
2 years ago
Basic math equations and calculations play an important role in many jobs tasks. If you were working at a grocery store and your
OverLord2011 [107]

Given :

Price of cereal without off, C = $2.88 .

Percentage off, P = 20% .

To Find :

Price after applying 20% off.

Solution :

Final price = Initial price - 20 % of initial price

F = 2.88 - 2.88\times \dfrac{20}{100}\\\\F=2.88-0.576\\\\F=\$ 2.304

Therefore, final price after sale is $2.304 .

Hence, this is the required solution.

8 0
2 years ago
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