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Schach [20]
2 years ago
9

On your first day as an apprentice at the oil refinery, you are asked to create usable graphs and tables for the other workers w

ho fill the oil tankers.
You are given the following information to assist you with your assigned task at the oil refinery:

An oil tanker holds approximately 1,785,000 gallons of petroleum product. The refinery has two hoses that can be used to fill a tanker, a large one and a small one. On an average day, it takes 20 hours to fill an empty tank with the largest hose and 30 hours with the smallest hose.

Determine the constant rate of change in the hold of the tanker for each hose.
Mathematics
1 answer:
Naya [18.7K]2 years ago
4 0

Answer:

89,250 gallons per hour

Step-by-step explanation:

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<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

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Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



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Answer:

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