Answer:
5.2 × 10 ⁹ cfus
Explanation:
Using the dilution factors
0.1 ml of the final dilution has 52 colonies
1 ml will have approximately 520 colonies
10 ml of the final sample will have 5200 colonies
at 1 / 100 dilution
1 ml of the sample will have 5200 colonies
100 ml of the sample will have 520000 colonies
1 ml of the 0.1 ml + 9.9 ml has 520000 colonies
10 ml will have 5200000
at the second stage of the dilution
0.1 ml of the slurry had 5200000 colonies
1 ml will have 52000000 colonies
10 ml will have 520000000 colonies
100 ml of the initial sample ( 10 grams + 90 ml ) = 5200000000 colonies =
5.2 × 10 ⁹ cfu
Answer:
In the extracellular space
Explanation:
Disulfide bonds are interconnections between chains (or between parts of a chain) formed by the oxidation of cysteine radicals, this reaction is catalyzed by specific enzymes.
Intracellular proteins have no disulfide bonds, which are more common in proteins secreted into the extracellular environment.
Disulfide bonds do not form in the cytoplasm because there are a lot of reducers in the cytoplasm (intracellular environment) , making the disulfide bonds unstable. The reducing environment of cytoplasm causes disulfide bonds (S-S) to return to the form of cysteine groups (-SH).
A protein is a large sequence of amino acid that was translated in ribosomes (or rough endoplasmic reticulum) from a mRNA that was transcribed in the nucleus from DNA.
If the protein has an extracellular function (like immunoglobulin) if should be
exocytosed from the cell.
The protein in the cell is driven to the membrane into
vesicles that have
a specific receptor, which allows, while in contact with the inner side of the cell membrane to open it and let the protein being transported in the extracellular medium.
Answer:
I think the answer is B
Explanation:
Because using logic on this situations is best idk