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2 years ago

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The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation I (d B) = 10 log left-bracket

StartFraction I Over I Subscript 0 Baseline EndFraction Right-bracket, where I is the intensity of a given sound and I0 is the threshold of hearing intensity. What is the intensity, in decibels, [I(dB)], when I = 10 Superscript 32 Baseline (I Subscript 0)?

2 answers:

laila [671]2 years ago

7 0

Answer:

<h2>The intensity in decibel is 320 decibel </h2>

Step-by-step explanation:

Given the intensity, or loudness, of a sound measured in decibels (dB), according to the equation $I (dB)= 10log(\frac{I}{Io} )$ where;

I is the intensity of a given sound and

$Io$ is the threshold of hearing intensity

To get I(dB) when $I=10^{32} Io$

We will substitute the value of I = $I=10^{32} Io$ into the equation above to have;

$I (dB)= 10log(\frac{10^{32}Io }{Io} )\\I(dB)=10log10^{32}\\ I(dB)=32*10log10\\$

Since log10 = 1;

$I(dB)=32*10(1)\\I(dB)=320$

The intensity in decibel is 320 decibel

777dan777 [17]2 years ago

7 0

Answer:

correct answer is 737 or d on ( e d g e )

Step-by-step explanation:

cause

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Step-by-step explanation:

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a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

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