Answer:
The answer to this question is given in the explanation section. The correct option is long tail
Explanation:
a.Folksonomy
Folksonomy is a way of organizing data and digital content. With Web 2.0, users can collaboratively manage and tag photos, journals and other media. As more users do this, creates a system of classification for the media and information. so this option is not correct
b. long tail (correct option)
Some sites are able to offer services as well in which users can subscribe monthly or pay a fee every so often. An example of this would be Netflix.
c.user participation
All users have the free will to contribute to the site which makes many Web 2.0 pages public. With sites such as Wikipedia, anyone is open to the editing of articles. Information is provided two-way instead of solely from the site owner.
d.application
Web 2.0 applications that allow anyone to create and share online information or material they have created. As you know that there are number of different types of web 2.0 applications including wikis, blogs, social networking, folksonomies, podcasting & content hosting services.
Answer:
False.
Explanation:
I believe this should be the work of a compliance liaison. Assume you have opened up an organization that is growing each day. You have employees who are required to be compliant with all the security standards and policies. Hiring a compliance liaison will ensure that these compliances are being carried out. Each department in an organization should work with a compliance liaison to ensure that its employees understand and comply fully with all security policies.
Answer:
To avoid conflicting uses of A register, few well-written programs follow the best practice, i.e, avoiding reference to M and vice versa. The programmer can use the A register to select either a data memory location for a subsequent C-instruction involving M, or an instruction memory location for a subsequent C-instruction involving a jump. Thus, to prevent the conflicting use of the A register, in well-written programs a C-instruction that may cause a jump (i.e., with some non-zero j bits) should not contain a reference to M, and vice versa.
Image is attached for better demonstration and understanding.
Answer:
A company requires an Ethernet connection from the north end of its office building to the south end. The distance between connections is 161 meters and will need to provide speeds of up to 10 Gbps in full duplex mode. Which of the following cable combinations will meet these requirements?
ANSWER: Use multi-mode fiber optic cable
Explanation:
MULTI-MODE FIBER OPTIC CABLE
For Ethernet distances up to 100 meters, the Copper CATX cable will do just fine. In the question, we are dealing with a distance of up to 161 meters, so we need an Ethernet extension. LAN extension over fiber optic cable with media converter can be used to convert the Ethernet cable runs from copper to fiber. Multi-mode fiber has a range of 550 meters for 10/100/1000 Ethernet links.
Multi-mode optical fiber is commonly used for communication over short distances, like within a building or on a campus. They are capable of data rate of up to 100 Gbps, which surpasses the requirements in this question. They are more economical in this case as they are not as expensive a the single-mode optical fiber cable. Fiber optic cable has the advantage of being immune to electromagnetic interferences, spikes, ground loops, and surges. This makes it more suited for this purpose.
Answer:
The code to this question can be given as:
Code:
int i,j,count_previous=0,count_next=0; //define variable
for (j=0; j<n; j++) //loop for array
{
if (x[0]==x[j]) //check condition
{
count_previous++; //increment value by 1.
}
}
for (i=0; i<n; i++) //loop
{
for (j=0; j<n; j++)
{
if (x[i]==x[j]) //check condition
{
count_next++; //increment value by 1.
}
}
if (count_previous>count_next) //check condition
{
mode=x[i-1];
}
else
{
mode=x[i];
count_previous=count_next; //change value.
count_next= 0 ; //assign value.
}
}
Explanation:
In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.
