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2 years ago

Express 30p as a fraction of £3.00

Mathematics

1 answer:

neonofarm [45]2 years ago

4 0

Answer:

$\frac{1}{10} \£$

Step-by-step explanation:

We know that £1 equals 100p.

Knowing this relation, we can use the rule of three

$30p \times \frac{ \£1}{100p} =0.3 \£$

Then, we form the fraction

$\frac{0.3 \£}{\£ 3.00} =\frac{3}{30} =\frac{1}{10} \£$

Therefore, the fraction of of £3.00 is

$\frac{1}{10} \£$

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The scale of map is 4cm: 1km, the simplest possible ratio is a. 1cm: 250m b. 3cm: 560m c. 2cm: 340m

Zolol [24]

Answer:

1 cm : 250 m

Step-by-step explanation:

the scale is 4 cm : 1 km

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Liliana used 444 dark power crystals to raise 141414 zombie soldiers. She wants to know how many zombie soldiers (z)(z)left pare

Mariulka [41]

Question is bit incorrect, Correct question is given below.

Liliana used 4 dark power crystals to raise 14 zombie soldiers. She wants to know how many zombie soldiers (z) she can raise with 10 dark power crystals. How many zombie soldiers can Liliana raise with 10 power crystals?

Answer:

Liliana can raise 35 zombie soldiers.

Step-by-step explanation:

Let the number of zombie soldiers raised by 10 dark power crystals be 'z'.

Zombie raised by 4 power crystals = 14

Since the number of zombie and power crystals are in direct proportion.

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$\frac{z}{10}=\frac{14}{4}$

Multiply 10 on both the sides, we get

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2 years ago

In a box containing 25 cherries, 2 of them are rotten. Susan randomly picks cherries in the box. How many cherries should be pic

bezimeni [28]

Answer:

Susan should pick 6 cherries from box, so the probability of picking the 2 rotten cherries is 1/20

Step-by-step explanation:

assuming that each cherry is equally probable to be chosen , since each cherry is independent from the others and sampling is done without replacement , the random variable X= number of cherries that are rotten from the picked ones follows a hyper geometrical distribution , where

P(X=k)= C(M,k) * C(N-M, n-k) / C(N,n)

where

N= population size = 25

n= number of picks

M = total number of rotten cherries =2

k = number of rotten cherries picked =2

C( ) = combination

then

1/20=C(2,2)*C(25-2,n-2)/C(25,n) = 1 * (23!/(n-2)!*(25-n)! / (25!/(n!*(25-n)!

1/20 = n!/(n-2)! * 1/(24*25)

24*25/20 = n*(n-1)

n²-n-30 =0

n= (1 +√(1+4*1*30))/2 = 12/2= 6

n=6

then Susan should pick 6 cherries from box, so the probability of picking the 2 rotten cherries is 1/20

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2 years ago

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