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FinnZ [79.3K]
2 years ago
6

Kim is reading a book with 380 pages. She read 20 pages each day until she reached Part 2 of the book. Part 2 of the book is 160

pages long. She uses the equation 380−20d=160380-20d=160 to represent the number of days, d, it took her to read Part 1. How many days did it take Kim to read Part 1 of the book? CLEAR SUBMIT 8 days 11 days
Mathematics
2 answers:
d1i1m1o1n [39]2 years ago
6 0
If you divide 380 by 20, you get 19. To check this, multiply 20 x 19 to see 380. Hope this helps :D
alexdok [17]2 years ago
3 0

Answer:

It take 11 days to read the first part of the book.

Step-by-step explanation:

As I can see the book has two parts, the total of the book is 380 pages and the second part is 160, so the pages of the first part of the book will be:

1part=380-160=220

From this we can see, that the first part will take:

\frac{220}{20}=11days

The first part will take 11 days.

Now from the equation proposed in the argument, we can see that we can calculate also the days that the first part took:

380-20d=160

Clearing it:

380-160=20d\\d=\frac{380-160}{20}\\ d=\frac{220}{20}\\ d=11\\

It take 11 days to read the first part of the book.

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According to a Pew Research survey, about 27% of American adults are pessimistic about the future of marriage and the family. Th
IgorLugansk [536]

Answer:

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Step-by-step explanation:

Using the binomial model, the probability that x adults from the sample, are pessimistic about the future is calculated as:

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Where n is the size of the sample and p is the probability that an adult is pessimistic about the future of marriage and family. So, replacing n by 20 and p by 0.27, we get:

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Now, 25% of 20 people is equal to 5 people, so the probability that, in a sample of 20 American adults, 25% or fewer of the people are pessimistic about the future of marriage and family is equal to calculated the probability that in the sample of 20 adults, 5 people of fewer are pessimistic about the future of marriage and family.

Then, that probability is calculated as:

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P(0)=\frac{20!}{0!(20-0)!}*0.27^{0}*(1-0.27)^{20-0}=0.0018

P(1)=\frac{20!}{1!(20-1)!}*0.27^{1}*(1-0.27)^{20-1}=0.0137

P(2)=\frac{20!}{2!(20-2)!}*0.27^{2}*(1-0.27)^{20-2}=0.0480\\P(3)=\frac{20!}{3!(20-3)!}*0.27^{3}*(1-0.27)^{20-3}=0.1065\\P(4)=\frac{20!}{4!(20-4)!}*0.27^{4}*(1-0.27)^{20-4}=0.1675\\P(5)=\frac{20!}{5!(20-5)!}*0.27^{5}*(1-0.27)^{20-5}=0.1982

Finally, P(X≤5) is equal to:

P(X≤5) = 0.0018+0.0137 + 0.0480 + 0.1065 + 0.1675 + 0.1982

P(X≤5) = 0.5357

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