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FinnZ [79.3K]
2 years ago
6

Kim is reading a book with 380 pages. She read 20 pages each day until she reached Part 2 of the book. Part 2 of the book is 160

pages long. She uses the equation 380−20d=160380-20d=160 to represent the number of days, d, it took her to read Part 1. How many days did it take Kim to read Part 1 of the book? CLEAR SUBMIT 8 days 11 days
Mathematics
2 answers:
d1i1m1o1n [39]2 years ago
6 0
If you divide 380 by 20, you get 19. To check this, multiply 20 x 19 to see 380. Hope this helps :D
alexdok [17]2 years ago
3 0

Answer:

It take 11 days to read the first part of the book.

Step-by-step explanation:

As I can see the book has two parts, the total of the book is 380 pages and the second part is 160, so the pages of the first part of the book will be:

1part=380-160=220

From this we can see, that the first part will take:

\frac{220}{20}=11days

The first part will take 11 days.

Now from the equation proposed in the argument, we can see that we can calculate also the days that the first part took:

380-20d=160

Clearing it:

380-160=20d\\d=\frac{380-160}{20}\\ d=\frac{220}{20}\\ d=11\\

It take 11 days to read the first part of the book.

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If you take the other numbers and subtract each from the original 236, they all exceed the amount. So the answer would be 113.

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8.25 pounds

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Olivia counted the number of ladybugs on each plant in her garden, then made the graph below.
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2 years ago
If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ?
KIM [24]

Answer:

The answer is

sin(\theta)=-\frac{\sqrt{2}}{2}

tan(\theta)=-1

Step-by-step explanation:

we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

sin^{2}(\theta)+cos^{2}(\theta)=1

In this problem we have

cos(\theta)=\frac{\sqrt{2}}{2}

\frac{3\pi}{2}

so

The angle \theta belong to the third or fourth quadrant

The value of sin(\theta) is negative

Step 1

Find the value of  sin(\theta)

Remember

sin^{2}(\theta)+cos^{2}(\theta)=1

we have

cos(\theta)=\frac{\sqrt{2}}{2}

substitute

sin^{2}(\theta)+(\frac{\sqrt{2}}{2})^{2}=1

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sin^{2}(\theta)=\frac{1}{2}

sin(\theta)=-\frac{\sqrt{2}}{2} ------> remember that the value is negative

Step 2

Find the value of tan(\theta)

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

we have

sin(\theta)=-\frac{\sqrt{2}}{2}

cos(\theta)=\frac{\sqrt{2}}{2}

substitute

tan(\theta)=\frac{-\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}}

tan(\theta)=-1

8 0
2 years ago
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