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2 years ago

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NL and MK are diameters of circle J. Complete the statements about circle J. MP is a major arc/minor arc and measures __ degrees

. MLN is a minor arc/major arc/semicircle and measures __ degrees.

1 answer:

joja [24]2 years ago

3 0

Answer:

1. Minor arc

2. 152

3. major arc

4. 298

Step-by-step explanation:

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Ben and Landon took turns driving on their recent 820 mile road trip. Ben averaged 60 miles per hour while landon averaged 56 mi

Furkat [3]

Landon drove for 5 hours.

<u>Step-by-step explanation</u>:

Given that,

Total distance of the road trip = 820 miles

Speed of Ben = 60 miles per hour

Speed of Landon = 56 miles per hour

<u><em>Step 1 </em></u><em>:</em>

Let 'x' be the number of miles Ben drove

Let 'y' be the number of miles Landon drove

<u><em>Step 2</em></u><em> :</em>

The trip took them 14 hours to complete 820 miles together.

x + y = 14

60x + 56y = 820

<u><em>Step 3 </em></u><em>:</em>

Solve the linear system x+ y= 14 and 60x+ 56y= 820

x + y = 14

x = 14 - y

<u><em>Step 4 </em></u><em>:</em>

Substitute x= 14-y in the second equation,

60(14-y) + 56y = 820

840 - 60y + 56y = 820

<u><em>Step 5</em></u><em> :</em>

Keeping y terms on one side and constants on other side,

60y - 56y = 840 - 820

4y = 20

y = 20/4

y = 5

Since 'y' is the number of miles Landon drove, the time Landon drove is 5 hours.

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2 years ago

Jillian is selling boxes of cookies to raise money for her basketball team. The 10 oz. box costs $3.50, while the 16 oz. box cos

cluponka [151]

<span>we have to solve simultaneous equations.

x = 10 oz. boxes

y = 16 oz. boxes

simultaneous equations

x + y = 24 ---1)

3.50x + 5.00y = 97.50 ----2)

to solve for x we need to eliminate y, therefore we have to multiply 1st equation by 5

5x + 5y = 120 --3)

subtract 3) - 2)

5x - 3.50x = 120 - 97.50

1.50x = 22.5 x = 15

number of 10 oz. boxes are 15. answer is d.15</span>

6 0

2 years ago

Read 2 more answers

Horatio is solving the equation Negative three-fourths + two-fifths x = StartFraction 7 Over 20 EndFraction x minus one-half. Wh

nata0808 [166]

Answer:

x = 5

Step-by-step explanation:

Step 1: Write equation

-3/4 + 2/5x = 7/20x - 1/2

Step 2: Subtract 7/20x on both sides

-3/4 + 1/20x = -1/2

Step 3: Add 3/4 to both sides

1/20x = 1/4

Step 4: Divide 1/20 on both sides

x = 5

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2 years ago

A company with $60,000 in sales last year had $69,000 in sales this year. Assuming the company's sales continue to grow at the s

aalyn [17]

Subtract 69000 from 60000. Answer becomes 9000. So you add 9000 to 69000 2 times. Your answer becomes 87000.

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2 years ago

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Below are boxplots that summarize the weights (in pounds) of large samples from two breeds of dog: the Anatolian Shepherd and th

koban [17]

Answer:

(a) The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of both plots is also same that is 75 pounds.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively

(b) Any data point which is greater than 155 or smaller than 80 will be considered an outlier.

Step-by-step explanation:

A box plot is a graph which shows five statistical characteristics of a data set.

1. Maximum value

2. Minimum value

3. Median

4. Upper Interquartile

5. Lower interquartile

(a) Compare the distributions of weights for the two dog breeds

Please refer to the attached diagram of the question.

The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of Anatolian Shepherd is,

Range = Maximum value - Minimum value

Range = 175 - 100 = 75 pounds

The range of Black Russian Terrier is,

Range = Maximum value - Minimum value

Range = 155 - 80 = 75 pounds

Therefore, the range of both plots is also same that is 75 pounds.

A box-plot is considered to be normally distributed when the median is at the center of upper quartile and lower quartile.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively distributed.

(b) What weights would a Black Russian Terrier have to be to be considered an outlier?

An outlier is a data point in the data set that is very different from the other data points.

In this case, the maximum and minimum values in the Black Russian Terrier box-plot are

Maximum = 155

Minimum = 80

Therefore, any data point which is greater than 155 or smaller than 80 will be considered an outlier.

5 0

2 years ago