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Irina18 [472]
2 years ago
15

If f(x) = 6x - 4, what is f(x) when x = 8? 2. 16 044 52

Mathematics
1 answer:
Virty [35]2 years ago
8 0

Answer:

44

Step-by-step explanation:

f(x) = 6x - 4

f(8) = 6(8) - 4

f(8) = 48 - 4

f(8)= 44

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2 years ago
What is the value of x when y=10 in the equation y=4x-2
Viefleur [7K]
Substitute y for 10 in the equation and solve using these steps:
10=4x+2
1) Minus 2 from both sides
8=4x
2) Divide both sides by 4 (the coefficient of x)
2=x
The value of x is 2 and we can check this by substituting it back into the original equation, 10 = (4×2)+2.
3 0
2 years ago
In an experiment, some diseased mice were randomly divided into two groups. One group was given an experimental drug, and one wa
damaskus [11]

Answer:

D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.

Step-by-step explanation:

We will test the hypothesis on the difference between means.

We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).

Then, the difference between means is:

M_d=M_1-M_2=18.2-15.9=2.3

If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{2.3-(0)}{1.1}=2.09

The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.

This is approximately 2 standards deviation (z=2).

The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.

4 0
2 years ago
Triangle $ABC$ has altitudes $\overline{AD},$ $\overline{BE},$ and $\overline{CF}.$ If $AD = 12,$ $BE = 14,$ and $CF$ is a posit
Shalnov [3]

Answer:

<u>CF = 7</u>

Step-by-step explanation:

Given: Δ ABC

Altitudes ⇒ AD = 12 , BE = 14  and  CF = ?

The area of the triangle = 0.5 AD * BC ⇒ (1)

OR area                          = 0.5 BE * AC  ⇒ (2)

OR area                          = 0.5 CF * AB  ⇒ (3)

By equating (1) and (3)

∴ 0.5 CF * AB = 0.5 AD * BC

∴ CF = \frac{AD*BC}{AB} =\frac{12BC}{AB} ⇒ (4)

By equating (1) and (2)

0.5 BE * AC = 0.5 AD * BC

∴ \frac{AC}{BC} = \frac{AD}{BE} =\frac{12}{14} =\frac{6}{7} (5)

We should know that about the relation between the sides of the triangle:

The sum of two sides will be greater than the third side

So, AB < BC + AC    ⇒ divide both sides by BC

∴ \frac{AB}{BC} < 1+\frac{AC}{BC}

By substitution from (5) with AC/BC

∴ \frac{AB}{BC}

∴ \frac{AB}{BC}

∴ \frac{BC}{AB} > \frac{7}{13} ⇒ (6)

By substitution from (6) at (4)

∴ CF > 12 * 7/13

CF > 6.46

But CF is a positive integer

<u>∴ CF = 7</u>

4 0
2 years ago
In the equation "y=m+b," what does the "m" stand for​
Furkat [3]

The m in y=mx+b stands for the slope of the line

Hope this helps!

5 0
2 years ago
Read 2 more answers
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