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Cerrena [4.2K]
2 years ago
15

PLEASE HELP ASAP I always give brainliests!

Mathematics
1 answer:
nlexa [21]2 years ago
7 0

first to find average age add all the ages divide by number of ages 4

5+4=9

9+6=15

15+39=54

54/4=13.5

For standard deviation find the mean/average

13.5

then subtract the mean from each number/age

5-13.5=-8.5

4-13.5=-9.5

6-13.5=-7.5

39-13.5=25.5

then square each number

-8.5^2=-72.25

-9.5^2=-90.25

-7.5^2=-56.25

25.5^2=650.25

then find the mean/average of the new numbers

-72.25+-90.25+-56.25+650.25=431.5

431.5/4=107.85

then take the square root of the new mean/average

\sqrt{ 107.875}\\10.38628903...

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Consider a sample with a mean of 500 and a standard deviation of 100. What are the z-scores for the following data values: 560,
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Answer:

z-score for value 560 = 0.6

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z-score for value 450 = -0.5

z-score for value 300 = -2

Step-by-step explanation:

We are given a sample with a mean of 500 and a standard deviation of 100.

i.e., \mu = 500 and \sigma = 100

The z score distribution is given by;

              Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where X represents the data values;

  • So, z score for value 560 is;

                 z score = \frac{560-500}{100} = 0.6

  • So, z score for value 650 is;

                 z score = \frac{650-500}{100} = 1.5

  • So, z score for value 500 is;

                 z score = \frac{500-500}{100} = 0

  • So, z score for value 450 is;

                 z score = \frac{450-500}{100} = -0.5

  • So, z score for value 300 is;

                 z score = \frac{300-500}{100} = -2

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Answer: The answer is going to be 7


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