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mote1985 [20]
2 years ago
15

If x2=y3, what is the value of z does x3z=y9?

Mathematics
1 answer:
arlik [135]2 years ago
8 0

If x² = y³ , for what value of z does x^{3z} =  Y^{9}  ?

Answer:

z= 2

Step-by-step explanation:

To solve the question given, we will follow the steps below;

X^{3z} =  Y^{9}   -----------------------------------------------------------------(1)

but   applying the law of indices mᵃᵇ = (mᵃ)ᵇ

then

Y^{9}  = (Y^{3})^{3}

replace  Y^{9}  by  (Y^{3})^{3}  in equation (1)

X^{3z} =  Y^{9}

X^{3z} =   (Y^{3})^{3}   --------------------------------------------------------------------(2)

but  from the question x² = y³

replace y³ by x²  in equation (2)

X^{3z} =   (Y^{3})^{3}

X^{3z} =   (X^{2})^{3}

X^{3z} =   X^{6}

3z = 6

divide both-side of the equation by 3

3z/3 = 6/3

On the left-hand side of the equation, 3 at the numerator will cancel-out 3  at the denominator leaving us with just z while on the right-hand side of the equation 6 will be divided by 3

z= 2

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Mr Chua borrows a sum of money from the bank which charges a compound interest of 4.2% per annum, compounded 6.Given that Mr Chu
Inessa [10]

Answer:

Original sum of money = $2246.51

Step-by-step explanation:

Interest = $96.60

Interest is compounded 6 times in a year ; n = 6

time = 1 year ; Rate of interest (r) = 4.2%

Interest = Future Value - Principal Value ...........(1)

\text{Future Value = }Principal\cdot (1+\frac{r}{100\times n})^{n\cdot t}\\\\\text{Substituting this value in equation (1) , We get }\\\\Interest=Principal\cdot (1+\frac{r}{100\times n})^{n\cdot t}-Principal\\\\\implies 96.60=Principal[\cdot (1+\frac{4.2}{100\times 6})^{6\cdot 1}-1]\\\\\implies Principal=\$2246.51

Hence, the original sum of money borrowed = $2246.51

4 0
2 years ago
A researcher wants to estimate the mean weekly family expenditure on clothing purchases and maintenance. First, she needs to det
Blizzard [7]

Answer: C. 461

Step-by-step explanation:

We know that the formula to find the sample size is given by :-

n=(\dfrac{z^*\cdot \sigma}{E})^2

, where \sigma = Population standard deviation from prior study.

E = margin of error.

z* = Critical value.

As per given , we have

\sigma=125

E= 15

Significance level : \alpha=0.01

Critical value (Two tailed)=z^*=z_{\alpha/2}=z_{0.005}=2.576

Now , Required sample size = n=(\dfrac{(2.576)\cdot 125}{15})^2

n=(21.4666666667)^2\\\\ n=460.817777779\approx461 [Round to next integer]

Hence, the required sample size to be taken is 461.

Correct answer = C. 461

3 0
2 years ago
The total operating costs of a monorail are paid using a combination of passenger fares and tax revenue. The farebox recovery ra
Vadim26 [7]

Answer:

0.57 or 0.56

Step-by-step explanation:

passenger fares + tax revenue = operating costs

Thus:

passenger fares = operating costs - tax revenue

= $69 million - $30 million

= $39 million

The ratio of passenger fares to total operating costs is:

$39 million

= 0.5652.

$69 million

To the nearest hundredth, the farebox recovery ratio is 0.57.

4 0
1 year ago
What is the ratio of the area of sector ABC to the area of sector DBE?
shusha [124]

We have to find the" ratio of the area of sector ABC to the area of sector DBE".

Now,

the general formula for the area of sector is

Area of sector= 1/2 r²θ

where r is the radius and θ is the central angle in radian.


180°= π rad

1° = π/180 rad


For sector ABC, area= 1/2 (2r)²(β°)

= 1/2 *4r²*(π/180 β)

= 2r²(π/180 β)

For sector DBE, area= 1/2 (r)²(3β°)

= 1/2 *r²*3(π/180 β)

= 3/2 r²(π/180 β)

Now ratio,

Area of sector ABC/Area of sector DBE =\frac{2r^{2}*\ \frac{\pi}{180} beta}{3/2 r^{2}*\ \frac{\pi}{180}beta}

= 4/3

7 0
2 years ago
Read 2 more answers
Part A: During what interval(s) of the domain is the water balloon's height increasing?
Advocard [28]

Answer:

The answer is below

Step-by-step explanation:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.

Answer:

Part A: During what interval(s) of the domain is the water balloon's height increasing?

Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet

Part B: During what interval(s) of the domain is the water balloon's height staying the same?

Between 2 and 4 seconds, the height remains the same at 75 feet. Also from 10 seconds the height of the balloon is at 0 feet

Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest?

Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet (i.e. -17.5 ft/s)

Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet (i.e. -10 ft/s)

Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet (i.e. -10 ft/s)

Hence it decreases fastest from 4 to 6 seconds

Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds

From 10 seconds, the balloon is at the ground, so it remains at the ground (0 feet) even at 16 seconds

6 0
2 years ago
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