<u>Given</u>:
Given that the regular decagon has sides that are 8 cm long.
We need to determine the area of the regular decagon.
<u>Area of the regular decagon:</u>
The area of the regular decagon can be determined using the formula,

where s is the length of the side and n is the number of sides.
Substituting s = 8 and n = 10, we get;

Simplifying, we get;




Rounding off to the nearest whole number, we get;

Thus, the area of the regular decagon is 642 cm²
Hence, Option B is the correct answer.
Answer:
<h2>y=25p-45</h2>
Step-by-step explanation:
We first of all start by cumulating all the time she spent for break
lunch= 30min
break= 15min
total break= 45min
also the time taken to assemble one model plane 25min
let the number of hours be p
and the total number of model plane be y
The model is
y=25p-45
Answer:
Step-by-step explanation:
The mentioned relationship for the weight, in pounds, of the kitten with respect to time, in weeks, is

Weight of the kitten after 10 weeks

pounds
This modeled equation is based on the observation of the early age of a kitten where the kitten is in its growth period, but in the early stage the growth rate in the weight of the kitten was the same but the growth of any living beings continues till the adult stage. So, after some time, in real life situation, this weekly change in weight will become zero, So, this model is not suitable to measure the weight of the kitten over the larger time period.
Here, t= 10 weeks is nearby the observed time period, so the linearly modeled equation can be used to predict the weight.
Hence, the weight of the kitten after 10 weeks is 16.5 pounds.
Start with $30.25.
Subtract $14.00 to isolate the amount of money spent on admission.
30.25-14.00= 16.25. As a group $16.25 was spent on admission.
Admission is 3.25 per person. Divide 16.25 by 3.25.
16.25/3.25=5.
5 friends went ice skating.
The answer is
Letter D -
939.80.
You can refer to the attachment for the rate. Since he is forty-seven years old, use that age to find his rate under a twenty-year endowment insurance. In this case, the rate is 46.99. Multiply that rate to 20 since he purchased a 20-year endowment insurance with a face value of $20,000. (20,000/1,000 = 20)
46.99 x 20 = 939.80