The height of the project becomes zero when it hits the ground which is also the total time at which the projectile stays in the air. Equating the function to zero:
-10(x)(x - 4) = 0
The roots of this quadratic equation are:
x = 0, and x=4
Therefore, the projectile stays in the air for
4 seconds
Answer:
Equation shown
Step-by-step explanation:
Eq(1): x-3y=-12
X=-12+3y
=-4+y
Eq(2): x-3y=-6
X=-6+3y
=-2+y
For this question, you need to understand how to divide fractions.First we line up our fractions appropriately:
4/9 ÷ 4/5 = ? (You want to divide 4/9 by 4/5)
4/9 × 5/4 = ? (Now we use the reciprocal of 4/5 and multiply instead of divide)
4 x 5 = 20 and 9 x 4 = 36. (Cross multiply.)
20/36 = 5/9. (Simplify to lowest terms.)
So, 4/9 divided by 4/5 is 5/9!But 5/9 is more than 4/9, so the answer is 0 :PCorrect me if I'm wrong.
Answer:
8 hours
Step-by-step explanation:
$1,300/$32.50 = 40
$1,040/$32.50 = 32
40-32=8
Answer:
The equations that represent the reflected function are
Step-by-step explanation:
The correct question in the attached figure
we have the function
we know that
A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.
therefore
The reflection of the given function across the y-axis will be equal to
(Remember interchanges positive x-values with negative x-values)
An equivalent form will be
![f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}](https://tex.z-dn.net/?f=f%28x%29%3D5%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B%28-1%29%28x%29%7D%3D5%5B%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B-1%7D%29%5D%5E%7Bx%7D%3D5%285%29%5E%7Bx%7D)
therefore
The equations that represent the reflected function are
