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inessss [21]
2 years ago
9

A modified roulette wheel has 32 slots. One slot is​ 0, another is​ 00, and the others are numbered 1 through 30​, respectively.

You are placing a bet that the outcome is an odd number.​ (In roulette, 0 and 00 are neither odd nor​ even.) a. What is your probability of​ winning? The probability of winning is StartFraction 15 Over 32 EndFraction . ​(Type an integer or a simplified​ fraction.) b. What are the actual odds against​ winning? The actual odds against winning are
Mathematics
1 answer:
RUDIKE [14]2 years ago
5 0

Answer:

(a)\dfrac{15}{32}

(b) 17:15

Step-by-step explanation:

(a)

The roulette wheel has 32 slots (inclusive of 0 and 00)

Number of Odd Numbers between 1 to 30 =15

Since you are placing a bet that the outcome is an odd number.

P(\text{Winning})=\dfrac{\text{Number of Odd Numbers}}{\text{Total Number of Slots}} \\=\dfrac{15}{32}

(b) The actual odds against​ winning

\text{Actual Odds against Winning})=\dfrac{32-15}{15}\\=\dfrac{17}{15}

Therefore, the actual odds against​ winning are 17:15

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Calculate a23 for the product of the following matrices
s344n2d4d5 [400]

If A is the matrix product

A=\underbrace{\begin{pmatrix}1&2\\4&3\end{pmatrix}}_{M_1}\underbrace{\begin{pmatrix}6&1&5\\7&3&4\end{pmatrix}}_{M_2}

and a_{2,3} is the entry of A in the second row and third column, then

a_{2,3}=\begin{pmatrix}4&3\end{pmatrix}\begin{pmatrix}5\\4\end{pmatrix}=4\times5+3\times4=\boxed{32}

That is, the 2nd row, 3rd column entry of A is the product of the 2nd row of M_1 and the 3rd column of M_2.

6 0
2 years ago
Underage drinking, Part II: We learned in Exercise 3.25 that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008
Murrr4er [49]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: number of 18-20-year-olds that consume alcoholic beverages in a sample of 50.

The proportion of underage people that drinks are known to be p= 0.697

This variable is discrete. This experiment has two possible outcomes success or failure, we will call "success" each time we encounter an underage individual that consumes alcohol and "failure" will be counting an underage that does not consume alcohol. The number of repetitions of the trial is fixed n= 50. All randomly selected underage individuals are independent and the probability of success is constant trough the whole experiment p=0.697.

Then we can say that this variable has a binomial distribution and we will use that distribution to do the calculations.

a. Under a binomial distribution, the expected value is calculated as:

E(X)= n*p= 50*0.697= 34.85.

The variance of a binomial distribution is:

V(X)= n*p*(1-p)= 50*0.697*0.303= 10.55955

And the standard deviation is the square root of the variance:

√V(X)= 3.2495 ≅ 3.25

b. To know how rare the value 45, you have to see how distant it is concerning the expected value. For this you have to subtract the expected value and divide it by the standard deviation:

[X-E(X)]/√V(X)

(45-34.85)/3.25= 3.12

The value X=45 is 3.12 standard deviations above the mean, which means that it would be rare to find 45 people or more than consumed alcohol.

c. P(X≥45) = 1 - P(X<45)= 1 - P(X≤44)= 1 - 0.9994= 0.0006

I hope it helps!

8 0
2 years ago
How many bands uniforms can be made with 131 3/4 yards of fabric if each uniform requires 3 7/8
mafiozo [28]
<span>131 3/4 divided by 37/8.
   
527/4 divided by 31/8.
   
527/4 divided by 8/31.
   
1054/31.
   
34.</span>
3 0
2 years ago
the graph of f(x) shown below has the same shape as the graph of g(x)=x^2 but is shifted down 5 units and to the left 4 units (t
schepotkina [342]

Answer:

Option C

Step-by-step explanation:

A function g(x) = x² has been given as the parent function.

This function then shifted 5 units down.

Translated  function formed will be f(x) = x² - 5

Further this graph has been shifted 4 units to the left then the function will become

f(x) = [x - (-4)]² - 5

f(x) = (x + 4)² - 5

Therefore, option C is the answer.

6 0
2 years ago
Read 2 more answers
Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti
lesya [120]

Answer:

a) the sample size (n) = 156.25≅ 156

Step-by-step explanation:

<u>Step1 </u>:-

Given the two sample sizes are equal so n_{1} =n_{2} = n

Given the standard error (S.E) = 0.04

The standard error of the proportion of the given  sample size

S.E = \sqrt{\frac{pq}{n} }

Step 2:-

here we assume that the proportion of boys and girls are equally likely

p= 1/2 and q= 1/2

S.E = \sqrt{\frac{p(1-p)}{n} } \leq \frac{\frac{1}{2} }{\sqrt{n} }

\sqrt{n} = \frac{\frac{1}{2} }{S.E}

squaring on both sides, we get

n = \frac{1}{(2X0.04)^{2} }

on simplification, we get

n= 156.25 ≅ 156

sample size (n) = 156

<u>verification</u>:-

S.E = \sqrt{\frac{pq}{n} }= \sqrt{\frac{1}{4X156} } =\sqrt{0.0016}  

Standard error = 0.04

4 0
2 years ago
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