Question

For circle C, CG = CE, CG is perpendicular to FB, and CE is perpendicular to DA. What conclusion can be made? a circle with center C and chords FB and DA, a segment from C to chord FB intersects chord FB at G, and a segment from C to chord DA intersects chord DA at E

Answer 1

Answer:

A circle with center C has chords FB and DA which are equidistant from C.

Step-by-step explanation:

A chord is a straight line drawn from a point on the circumference of a circle to another point on the circumference, without passing through the center of the circle.

From the given question, a circle center C has two chords FB and DA that are equidistant from the center of the circle. The distant of FB from C is CG and the distance of DA from C is CE. But CG = CE, which implies that the two chords have equal distant from the center of the circle.

Therefore line CG from center C intersects FB at G, and line CE from center C intersects DA at E.