R = rate for the lawn sprinkler
rate of lawn sprinklerand hose would be 5 minutes /r ( rate per minute)
we would then want to add that to the ratio of the lawn sprinkler and hose together together which would be 5 minutes for both / 8 minutes for hose
we want to add those together to equal 100 percent, which can also be written as 1
so the correct equation would be B) 5/8 + 5/r = 1
Answer:
neither.
Step-by-step explanation:
Answer:
<h3>AC=96 units.</h3>
Step-by-step explanation:
We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.
, and CE=6x .
<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>
Therefore, AE = EC.
Plugging expressions for AE and EC, we get

Subtracting 6x from both sides, we get


Factoriong quadratic by product sum rule.
We need to find the factors of -16 that add upto -6.
-16 has factors -8 and +2 that add upto -6.
Therefore, factor of
quadratic is (x-8)(x+2)=0
Setting each factor equal to 0 and solve for x.
x-8=0 => x=8
x+2=0 => x=-2.
We can't take x=-2 as it's a negative number.
Therefore, plugging x=8 in EC =6x, we get
EC = 6(8) = 48.
<h3>AC = AE + EC = 48+48 =96 units.</h3>
Answer:
There cannot be equal errors in both and yellow has fewer errors.
Step-by-step explanation:
we can do paired t test for these two colours

(one tailed test)
df = 9
The data can be tabulated as follows:
Yellow white
5 7
2 6
6 8
7 5
2 9
5 11
3 8
8 3
4 6
9 10
t-Test: Paired Two Sample for Means
Yellow white
Mean 5.1 7.3
Variance 5.877777778 5.788888889
Observations 10 10
Pearson Correlation -0.139051655
Hypothesized Mean Difference 0
df 9
t Stat -1.908439275
P(T<=t) one-tail 0.044341411
t Critical one-tail 1.833112923
P(T<=t) two-tail 0.088682822
t Critical two-tail 2.262157158
Since p value one tailed = 0.0443 and it is <0.05 our significance level, we reject null hypothesis.
There cannot be equal errors in both and yellow has fewer errors.