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Morgarella [4.7K]
2 years ago
14

The distance around a circular dance hall room is 135 feet. Which of the following is closest to the longest distance across the

dance hall?
Mathematics
1 answer:
makkiz [27]2 years ago
6 0

Answer:

CD = \frac{135}{\pi }

Step-by-step explanation:

distance around a circular = CIRCUMFERENCE LENGTH = 2 * \pi * r

CL = 2 * \pi * r

135 = 2 * \pi * r

longest distance = circumference diameter (CD) = 2 * r

135 = 2 * \pi * r

135 = CD * \pi

CD = \frac{135}{\pi }

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On average, the number of customers who had items to return for refunds or exchanges at a certain retail store's service desk is
spayn [35]

Answer:

The probability that the service desk will have at least 100 customers with returns or exchanges on a randomly selected day is P=0.78.

Step-by-step explanation:

With the weekly average we can estimate the daily average for customers, assuming 7 days a week:

M=756/7=108

We can model this situation with a Poisson distribution, with parameter λ=108. But because the number of events is large, we use the normal aproximation:

P(\lambda)\approx N(\lambda,\lambda)

Then we can calculate the z value for x=100:

z=\frac{x-\mu}{\sigma}=\frac{100-108}{\sqrt{108}}=\frac{-8}{10.4} =-0.77

Now we calculate the probability of x>100 as:

P(x>100)=P(z>-0.77)=0.78

The probability that the service desk will have at least 100 customers with returns or exchanges on a randomly selected day is P=0.78.

5 0
2 years ago
Prof. okamoto selects 3 different students to report on 3 different current events. if there are 27 students in the class, in ho
kenny6666 [7]
Consider this option:
C³₂₇=27!/(3!*24!)=25*13*9=2925 ways to select 3 students.
8 0
2 years ago
Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?
AleksAgata [21]

we are given

12x^3-2x^2+18x-3

Firstly, we will split terms

2x^2*6x-1*2x^2+3*6x-1*3

We can group first two and last two terms

(2x^2*6x-1*2x^2)+(3*6x-1*3)

we can see that 2x^2 is common in first two terms

and 3 is common in last two terms

so, we can factor factor out 2x^2 from first group and 3 from second group

we get

=2x^2(6x-1)+3(6x-1)

we can see that each terms are multiple of 6x-1

so, we can factor out 6x-1

so, we get

12x^3-2x^2+18x-3 =(2x^2+3)(6x-1)............Answer


4 0
2 years ago
Read 2 more answers
The equation 4x2 – 24x + 4y2 + 72y = 76 is equivalent to
DerKrebs [107]

Answer:

Option 4 is correct.

The equation 4x^2 -24x + 4y^2 + 72y = 76 is equivalent to 4(x-3)^2 + 4(y+9)^2 =436

Step-by-step explanation:'

Given equation: 4x^2 -24x + 4y^2 + 72y = 76

First group the terms with x and those with y;

(4x^2-24x)+(4y^2+72y) = 76

Next, we complete the squares.

We can do this by adding a third term such that the x terms and the y terms are perfect squares.

For this we must either add the same value on the other side of the equation or subtract the same value on the same side so that the equality is maintained.

⇒4(x^2-6x) +4(y+18y) = 76

or

4(x^2 -6x +3^2 -3^2) + 4(y^2 +18y +9^2 -9^2) = 76

4(x^2-6x + 3^2) - 36 + 4(y^2+18y +9^2) - 324 = 76

4(x-3)^2 + 4(y+9)^2 - 360 =76

Add 360 on both sides we get;

4(x-3)^2 + 4(y+9)^2 =360 +76

Simplify:

4(x-3)^2 + 4(y+9)^2 =436

Therefore, the given equation is equivalent to 4(x-3)^2 + 4(y+9)^2 =436

5 0
2 years ago
BRAINLY ANYONE?
Oduvanchick [21]

Answer:

58, 37, 9

Step-by-step explanation:

Given:

First term a₁ = 65 and common difference d = - 7

This sequence is arithmetic series and formula for calculating n-th term is:

aₙ = a₁ + (n-1) d

Accordingly

The second term is:

a₂ = 65 + (2-1) (-7) = 65 - 7 = 58

a₂ = 58

The fifth term is:

a₅ = 65 + (5 - 1) (-7)  = 65 + 4 · (-7) = 65 - 28 = 37

a₅ = 37

The ninth term is:

a₉ = 65 + (9 - 1) (-7) = 65 + 8 · (-7) = 65 - 56 = 9

a₉ = 9

God with you!!!

4 0
2 years ago
Read 2 more answers
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