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Semmy [17]
2 years ago
10

John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, e

nd fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​
Engineering
1 answer:
sineoko [7]2 years ago
8 0

Question:

John read the first 114 pages of a novel, which was 3 pages less than ⅓ of the novel. Write an equation to determine the total number of pages (P)

Answer:

114 = ⅓P - 3

Explanation:

Given

Number of pages read = 114

Total pages in novel = p

The relationship between the pages read by John and the total pages is analysed as follows:

3 less than ⅓ of total pages means:

⅓ of total pages - 3

Recall that P represents the total pages in the novel

So, the expression becomes

⅓ * P - 3

⅓P - 3

This means that the pages read by John is ⅓P - 3

This implies that the equation to determine the number of pages in the novel is

⅓P - 3 = 114

Solving further to get the actual number of pages;

Multiply both sides by 3

3(⅓P - 3) = 114 * 3

3 * ⅓P - 3 * 3 = 114 * 3

P - 9 = 342

Add 9 to both sides

P - 9 + 9 = 342 + 9

P = 351

Hence the number of pages is 351

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Explanation:

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8 0
1 year ago
A 150-lbm astronaut took his bathroom scale (a spring scale) and a beam scale (compares masses) to the moon where the local grav
kozerog [31]

Answer:

a)Wt =25.68 lbf

b)Wt = 150 lbf

F= 899.59 N

Explanation:

Given that

g = 5.48 ft/s^2.

m= 150 lbm

a)

Weight on the spring scale(Wt) = m g

We know that

1\ lbf=32.17 \ lmb.ft/s^2

Wt = 150 x 5.48/32 lbf

Wt =25.68 lbf

b)

On the beam scale

This is scale which does not affects by gravitational acceleration.So the wight on the beam scale will be 150 lbf.

Wt = 150 lbf

If the plane is moving upward with acceleration 6 g's then the for F

F = m a

We know that

1\ ft/s^2= 0.304\ m/s^2

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a=6 g's

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3 0
2 years ago
. A cylindrical metal specimen having an original diameter of 12.8 mm (0.505 in.) and gauge length of 50.80 mm (2.000 in.) is pu
kogti [31]

Answer:

% reduction in area==PR=0.734=73.4%

% elongation=EL=0.42=42%

Explanation:

given do=12.8 mm

df=6.60

Lf=72.4 mm

Lo=50.8 mm

% reduction in area=((\pi*(do/2)^2)-(\pi*(df/2)^2)))/\pi*(do/2)^2

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% reduction in area=73.4%

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6 0
2 years ago
Explain why the fundamental software engineering principles of process, dependability, requirements management, and reuse are re
Svet_ta [14]

Answer:

1. Costs and frequency of change.

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3. The software lifetime and delivery schedule.

Explanation:

The process of requirement gathering is required in both generic and customized software.

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• Updating is required in each type of software. For doing so, new version of each type of software is released.

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5 0
2 years ago
Read 2 more answers
A hand crank generator is used to power a light bulb. The person turning the crank uses 22 Newtons of input force to turn the cr
ikadub [295]

Answer:

1. The input power is 17.6 Watts

2. The output power is 0.7232 Watts

3.The efficiency of the hand crank generator is approximately 4.109%

Explanation:

The given parameters are;

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The rate at which the crank is turned = 8 revolutions per 3 seconds

The distance the hand moves during each revolution = 0.3 meters

The current recorded by the multimeter = 0.08 amps

The voltage recorded by the multimeter = 9.04 volts

1. Power = The rate of doing work = Work done/(Time taken to do the work) = Force × Distance/Time

∴ The power input of the hand crank generator = 22 × 0.3 × 8/3 = 17.6 Watts

2. The power output to the bulb, P, is given by the formula for electrical power as follows;

Power = Current, I × Voltage V

∴ P = 0.08 ×  9.04 = 0.7232 Watts

3. Efficiency in percentage = Output/Input × 100

Therefore, the efficiency of the hand crank generator = )Output power/(Input power)) × 100 = (0.7232/17.6) × 100 ≈ 4.109%

8 0
2 years ago
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