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oksian1 [2.3K]
2 years ago
12

19. Seja 17x 51y+ 102. Qual é o valor de 9x 27y ? (A) 54 (B) 36 (C) 34 (D) 18 (E) indeterminado

Mathematics
1 answer:
lilavasa [31]2 years ago
4 0

Pergunta correta:

Seja 17x + 51y = 102. Qual é o valor de 9x + 27a? (A) 54 (B) 36 (C) 34 (D) 18 (E) indeterminado

Resposta: A) 54

Explicação passo a passo:

17x + 51y = 102 - - - - equação 1

Divulgue até 17

x + 3y = 6 - - - - - - - Equação 2

9x + 27y - - - - - - - equação 3

Comparando as equações 2 e 3

(Equação 3) = 9 × (equação 2)

Isso é, 9x + 27y = 9 × (x + 3y = 6)

9x + 27y = 9x + 27y = 54

Portanto ; 9x + 27y = 54

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Lets take Gregs weight as “x”. This means that Justins weight is x-15, and x/2 = (x-15)-75.

If we take that last equation, lets combine like terms:

x/2 = x - 15 - 75
x/2 = x - 90
Now multiply both sides by 2 to get rid of the fraction
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Subtract 2x from both sides
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x = 180 — this is Gregs weight

Justins weight is x-15, so 180-15, which is 165 pounds. Hope this helped.
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2 Rita bought three and forty-eight hundredths pounds of bananas at the store. How is this number written in expanded notation?
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this number written in expanded notation as : (3 × 1) + (4 × 0.1) + (8 × 0.01)

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Unless otherwise specified, the domain of a function f is assumed to be the set of all real numbers x for which f(x) is a real n
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Answer:

See Below

Step-by-step explanation:

The function is a piecewise function defined as:

N(t)=\left \{ {{25t+150} \ 0 \leq t \leq 6 \atop {\frac{200+80t}{2+0.05t} \ t \geq 8}} \right.

a)

We need to find the limit of the function as t goes to infinity. This means what is the max value of fish in the pond given times goes to infinity (on an on).

We will take the 2nd part of the equation since t falls into that range, t is infinity, which is definitely greater than 8.

\lim_{t \to \infty} \frac{200+80t}{2+0.05t} \\\lim_{n \to \infty} \frac{80t}{0.05t}\\ \lim_{n \to \infty} \frac{80}{0.05} =1600

This means the maximum number of fish at this pond is 1600, no matter how long it goes on.

b)

A function is continuous at a point if we have the limit and the functional value at that point same.

Functional value at t = 8 is (we use 2nd part of equation):

\frac{200+80t}{2+0.05t}\\\frac{200+80(8)}{2+0.05(8)}\\=350

We do have a value and limit also goes to this as t approaches 8.

So, function is continuous at t = 8

c)

We want to find is there a "time" when the number of fishes in the pond is 250, during t from 0 to 6. We plug in 250 into N(t) and try to find t. Make sure to use the 1st part of the piece-wise function. Shown below:

N(t)=25t+150\\250=25t+150\\25t=250-150\\25t=100\\t=4

The time is 4 years when the number of fishes in the pond is 250

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Answer:

B

Step-by-step explanation:

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