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oksian1 [2.3K]
2 years ago
12

19. Seja 17x 51y+ 102. Qual é o valor de 9x 27y ? (A) 54 (B) 36 (C) 34 (D) 18 (E) indeterminado

Mathematics
1 answer:
lilavasa [31]2 years ago
4 0

Pergunta correta:

Seja 17x + 51y = 102. Qual é o valor de 9x + 27a? (A) 54 (B) 36 (C) 34 (D) 18 (E) indeterminado

Resposta: A) 54

Explicação passo a passo:

17x + 51y = 102 - - - - equação 1

Divulgue até 17

x + 3y = 6 - - - - - - - Equação 2

9x + 27y - - - - - - - equação 3

Comparando as equações 2 e 3

(Equação 3) = 9 × (equação 2)

Isso é, 9x + 27y = 9 × (x + 3y = 6)

9x + 27y = 9x + 27y = 54

Portanto ; 9x + 27y = 54

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Step-by-step explanation:

Given :

Total number of people = 80

Total number of male = 24

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Number of female who use car = 17 out of 28

To find :

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Solution :

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Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil
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Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

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V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

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L = 5\,dados

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

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A = L^{2}

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A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

L \leq 125\,dados

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Esto nos lleva a decir que:

L < 11.180\,dados

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n = (11\,dados)^{2}

n = 121\,dados

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A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
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Answer:

a

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b

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c

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d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

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Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

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substituting values

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The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

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=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

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2 years ago
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