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Vanyuwa [196]
2 years ago
9

The triangles are congruent by SSS and HL. Triangles R S T and V W X are shown. Triangle R S T can be rotated about point S and

then shifted down and to the left to form triangle V W X. Which transformation(s) can be used to map △RST onto △VWX? reflection only translation only reflection, then translation rotation, then translation
Mathematics
2 answers:
NikAS [45]2 years ago
9 0

Answer:

rotation then translation

a_sh-v [17]2 years ago
7 0

Answer:

i believe its reflection then translation

Step-by-step explanation:

i think this because it you reflect it you are flipping it over and translation is just sliding it so if you reflect and translate it it will match STU

You might be interested in
What value is equivalent to 2 × 3 + 4 − 62?<br> A) -26 <br> B) -22 <br> C) -2 <br> D) 10
deff fn [24]

Hello from MrBillDoesMath!

Answer:

-52. None of the provided choices is correct

Discussion:

Following the usual order of math operations none of the provided answers is correct. The answer is

2*3 + 4- 62 =                => * before + and -

(2*3) + 4 - 62=             => 2*3 = 6

6 + 4 -62 =                   => 6 + 4 = 10

10 - 62 =

-52

Thank you,

MrB

6 0
2 years ago
Read 2 more answers
Akinte, Chuck, Jenny, and Norma are all going to college next year.
Licemer1 [7]

Answer and explanation:

Akinye Reynoso

Chuck peningan

Norma van hee

Jenny olowski

Akinte is not going to the University of Memphis nor university of Sierra tech nor university of Penn valley but goes to St Mary just like Reynoso(his surname)

Chuck is not going to St Mary nor Sierra tech nor Penn valley but goes to Memphis just like pennigan

Norman does not go to Memphis nor Penn valley nor St Mary but goes to Sierra tech just like van hee

Jenny does not go to Sierra tech nor St Mary nor Memphis but goes for Penn valley just like olowski

3 0
2 years ago
The gold bar has a trapezium cross-sectional area. Gold has a density of 19.3 grams per cm3. Work out the mass of the gold bar.
Varvara68 [4.7K]

Answer:

Mass of gold bar = 13.896 kg

Step-by-step explanation:

Volume of gold bar = Area of  trapezium x Length of bar

Length of bar = 16 cm

Area of  trapezium = 2 x Area of triangle + Area of rectangle

Area of triangle = 0.5 x 5 x 3 = 7.5 cm²

2 x Area of triangle = 2 x 7.5 = 15 cm²

Area of rectangle = 6 x 5 = 30 cm²

Area of  trapezium = 15 + 30 = 45 cm²

Volume of gold bar = 45 x 16 = 720 cm³

Density of gold = 19.3 g/cm³

Mass of gold bar = 720 x 19.3 = 13896 g = 13.896 kg

Mass of gold bar = 13.896 kg

6 0
2 years ago
Read 2 more answers
Pls explain your work!
mylen [45]

Answer:

find total volume to find what amount is 20%

hack, is put the 20% in alreadyy to find 20% volume

20%=1/5

so

vcone=1/3(hpir^2)

times thath by 1/5

vcone=1/15(hpir^2)

d/2=r

given

4.8=d

4.8/2=d/2=r=2.4

10=h

V=1/15(10pi2.4^2)

V=1/15(10pi5.76)

V=1/15(57.6pi)

V=3.84pi

V=12.0637 cubic inches=20% of vase

0.5 cubc inches per min

0.5 times t=12.0637

divide both sides by 0.5

t=24.1237

about 24 minutes

Step-by-step explanation:

6 0
2 years ago
What is the length of BC in the right triangle below?
dexar [7]

Answer:

D

Step-by-step explanation:

u can use Pythagorean theorem a2 + b2 =c2. c2 is the length of the hypotenuse. plug in 3 for a and 15 for b. 3 squared plus 15 squared equals c squared. 9+225= c2. 234=c2. answer is D. the square root of 234

8 0
2 years ago
Read 2 more answers
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