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xxMikexx [17]
2 years ago
7

Stealers, study components: In a study of the relationship between socio-economic class and unethical behavior, 129 University o

f California undergraduates at Berkeley were asked to identify themselves as having low or high social-class by comparing themselves to others with the most (least) money, most (least) education, and most (least) respected jobs. They were also presented with a jar of individually wrapped candies and informed that the candies were for children in a nearby laboratory, but that they could take some if they wanted. After completing some unrelated tasks, participants reported the number of candies they had taken. It was found that those who were identified as upper-class took more candy than others (Piff, 2012). Identify the following about this study.
a) What are the cases?_____
b) What are the variables and their types?_____
c) What is the main research question?_____
Mathematics
1 answer:
irga5000 [103]2 years ago
7 0

Answer:

a) 129 University of California undergraduates at Berkeley.

b) (i) social-class (ordinal), (ii) money (continuous), (iii) education (ordinal) , (iv) respected job (ordinal), (v) number of candies (continuous)

c) The main question is to find the relationship between socio-economic class and unethical  behaviour

Step-by-step explanation:

a) 129 University of California undergraduates at Berkeley.

b)

i) social-class (ordinal)

ii) money (continuous)

iii) education (ordinal)

iv) respected job (ordinal)

v) number of candies (continuous)

c) The main question is to find the relationship between socio-economic class and unethical  behaviour

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You have heard that customers will try a new caterer if the price is 20% below their existing caterer. Your competitor prices a
Evgesh-ka [11]

Answer:

b) $640

Step-by-step explanation:

Competitor's price  = $800

<u>Price, 20% below of competitor's:</u>

  • $800 - 20% =
  • $800*(100-20)/100 =
  • $800*0.8 =
  • $640

Correct answer choice is b) $640

3 0
2 years ago
let x = the amoun of raw sugar in tons a procesing plant is a sugar refinery process in one day . suppose x can be model as expo
anygoal [31]

Answer:

The answer is below

Step-by-step explanation:

A sugar refinery has three processing plants, all receiving raw sugar in bulk. The amount of raw sugar (in tons) that one plant can process in one day can be modelled using an exponential distribution with mean of 4 tons for each of three plants. If each plant operates independently,a.Find the probability that any given plant processes more than 5 tons of raw sugar on a given day.b.Find the probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day.c.How much raw sugar should be stocked for the plant each day so that the chance of running out of the raw sugar is only 0.05?

Answer: The mean (μ) of the plants is 4 tons. The probability density function of an exponential distribution is given by:

f(x)=\lambda e^{-\lambda x}\\But\ \lambda= 1/\mu=1/4 = 0.25\\Therefore:\\f(x)=0.25e^{-0.25x}\\

a) P(x > 5) = \int\limits^\infty_5 {f(x)} \, dx =\int\limits^\infty_5 {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_5=e^{-1.25}=0.2865

b) Probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day can be solved when considered as a binomial.

That is P(2 of the three plant use more than five tons) = C(3,2) × [P(x > 5)]² × (1-P(x > 5)) = 3(0.2865²)(1-0.2865) = 0.1757

c) Let b be the amount of raw sugar should be stocked for the plant each day.

P(x > a) = \int\limits^\infty_a {f(x)} \, dx =\int\limits^\infty_a {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_a=e^{-0.25a}

But P(x > a) = 0.05

Therefore:

e^{-0.25a}=0.05\\ln[e^{-0.25a}]=ln(0.05)\\-0.25a=-2.9957\\a=11.98

a  ≅ 12

6 0
2 years ago
A tile mosaic in the shape of a right triangle is used as the corner for a rectangular pathway. The hypotenuse of the mosaic is
Anit [1.1K]

Answer:

The lengths of the sides are 2.2 ft and 4.5 ft

Step-by-step explanation:

Let

a -----> the length of one side of the mosaic

b ----> the length of the other side of the mosaic

c ----> the hypotenuse of the mosaic

we know that

Applying the Pythagoras Theorem

c^{2}=a^{2}+b^{2} -----> equation A

we have

a=2b -----> equation B

c=5\ ft -----> equation C

substitute equation B and equation C in equation A and solve for b

5^{2}=(2b)^{2}+b^{2}

25=5b^{2}

b=\sqrt{5}=2.2\ ft

Find the value of a

a=2b ------> a=2\sqrt{5}=4.5\ ft

therefore

The lengths of the sides are 2.2 ft and 4.5 ft

6 0
2 years ago
Write the standard form of the line that contains a slope of and y-intercept of 3. Include your work in your final answer. Type
coldgirl [10]
Y=mx + b
m= slope
b= y intercept

y=3x + 3
7 0
2 years ago
Read 2 more answers
How many pounds of water must be evaporated from 50 pounds of a 3% salt solution so that the the remaining solution will be 5 %
svlad2 [7]

Answer:

Step-by-step explanation:

This is kinda tricky, but not nearly as bad as d = rt problems. Those are a nightmare!

We will make a table for this:

                         #lbs solution           *          % salt         =           lbs. salt

  3% solution

-  <u>Water                                                                                                      </u>

New solution

And we will now fill in what we know. The 3% solution part is easy. The number of pounds of that is 50 and the percent salt in 3% salt is....well, 3%. As a decimal, it is .03:

                             #lbs solution        *        %salt        =        lbs salt

  3% solution                50                 *          .03         =           1.5

-  <u>Water                                                                                                 </u>

New solution

The last column there with a 1.5 in it is the product of 50 times .03, since that is what the formula at the top of the table tells us we have to use. Now for the water. That's easy, too, since the amount of water we are evaporating (notice the subtraction sign out front of the word "water"; that indicates we are removing water) is our unknown, and we also know that water has 0% salt in it:

                          #lbs solution         *       %salt        =        lbs. salt

   3% solution            50                  *         .03         =           1.5

-   <u>Water                       x                  *            0          =            0         </u>

New solution

Now all we have left is the new solution row and the equation. Finding the equation from a mixture table is as easy as it can be! Super easy!

The new solution will be 50 - x since, going down column 1, we are subtracting the water from the 3% solution, the % salt is to be 5%:

                            #lbs. solution        *       %salt        =        lbs. salt

   3% solution               50                *         .03          =           1.5

-   <u>Water                          x                 *           0           =            0         </u>

New solution         50 - x                  *         .05          =     2.5 - .05x

Now we're ready for our equation. I got the 2.5 - .05x from multiplying

.05(50 - x), just so you know.

if we had to subtract the water from the salt solution and set it equal to the new solution in the first column, we also have to do it in the third column:

1.5 - 0 = 2.5 - .05x and solve for x:

-1 = -.05x so

x = 20 pounds of water

4 0
2 years ago
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