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dem82 [27]
1 year ago
14

Chris buys 8 more Ninja Turtles than Star Wars action figures. The Ninja Turtles cost $7 each and the Star Wars cost $9 each. Wr

ite an expression to model this situation, using S for Star Wars.
Mathematics
1 answer:
Natalka [10]1 year ago
4 0

Answer:

Total Cost, C=$(16S +56)

Step-by-step explanation:

Chris buys 8 more Ninja Turtles than Star Wars action figures.

Cost of each Ninja Turtle = $7

Cost of each Star Wars  = $9

Let number of Star Wars bought = S

As per question statement, number of Ninja Turtles bought = S+8

Cost of 'S' number of Star Wars = Number of Star Wars bought \times cost of each Star Wars

Total cost of Star Wars bought = S \times 9 or $9S

Similarly, Cost of 'S+8' number of Ninja Turtles = Number of Ninja Turtles bought \times cost of each Ninja Turtles

Total cost of Ninja Turtles bought = (S+8) \times 7 or $(7S +56)

Total Cost of the purchase = Total cost of Star Wars Bought + Total cost of Ninja Turtles bought

Total Cost of the purchase, C = 9S + (7S +56)

\Rightarrow C=\$(16S +56)

You might be interested in
How many pairs of whole numbers have a sum of 110
kap26 [50]

There are different definitions of "whole numbers".

Some define it as an integer (i.e. positive or negative) [some dictionaries]

Some define it as a non-negative integer. [most math definitions]

We will take the math definition, i.e. 0<= whole number < &infin;

To find pairs (i.e. two) whole numbers with a sum of 110, we start with

0+110=110

1+109=110

2+108=110

...

54+56=110

55+55=110

Since the next one, 56+54=110 is the same pair (54,56) as 54+56=110, we stop at 55+55=110  for a total of 56 pairs.

5 0
1 year ago
A. The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.
erastovalidia [21]

Answer:

The average yearly salary of  the architect is <u>$62,000</u> and the lawyer is <u>$100,000</u>.

Step-by-step explanation:

Given:

The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.

Combined, an architect and a lawyer earn $ 210 thousand.

Now, to find the average yearly salary of  an architect and a lawyer.

Let the average yearly salary of  an architect be x.

So, the average yearly salary of  the lawyer = 2x-24,000.

Combined, architect and lawyer earn = \$210,000.

Now, to get the average salary of the architect and lawyer:

x+(2x-24000)=210000

x+2x-24000=210000\\\\3x-24000=210000

<em>Adding both sides 24000 we get:</em>

3x=186,000\\\\Dividing\ both\ sides\ by\ 3\ we\ get:\\\\x=62000.

<u>The average salary of architect = $62,000.</u>

Now, to get the average salary of lawyer by substituting the value of x:

2x-24000\\\\=2(62000)-24000\\\\=124000-24000\\\\=\$100,000.

<u>The average salary of lawyer = $100,000.</u>

Therefore, the average yearly salary of  the architect is $62,000 and the lawyer is $100,000.

4 0
2 years ago
Page:<br>If A+B+C=180 , then prove that:cosA+cosB+cosC= 1+4SINA/2SINB/2SINC/2​
lakkis [162]

Answer:

A + B + C = π ...... (1)

...........................................................................................................

L.H.S.

= ( cos A + cos B ) + cos C

= { 2 · cos[ ( A+B) / 2 ] · cos [ ( A-B) / 2 ] } + cos C

= { 2 · cos [ (π/2) - (C/2) ] · cos [ (A-B) / 2 ] } + cos C

= { 2 · sin( C/2 ) · cos [ (A-B) / 2 ] } + { 1 - 2 · sin² ( C/2 ) }

= 1 + 2 sin ( C/2 )· { cos [ (A -B) / 2 ] - sin ( C/2 ) }

= 1 + 2 sin ( C/2 )· { cos [ (A-B) / 2 ] - sin [ (π/2) - ( (A+B)/2 ) ] }

= 1 + 2 sin ( C/2 )· { cos [ (A-B) / 2 ] - cos [ (A+B)/ 2 ] }

= 1 + 2 sin ( C/2 )· 2 sin ( A/2 )· sin( B/2 ) ... ... ... (2)

= 1 + 4 sin(A/2) sin(B/2) sin(C/2)

= R.H.S. ............................. Q.E.D.

...........................................................................................................

In step (2), we used the Factorization formula

cos x - cos y = 2 sin [ (x+y)/2 ] · sin [ (y-x)/2 ]

Step-by-step explanation:

6 0
2 years ago
After painting his porch, Jamil has \dfrac14 4 1 ​ start fraction, 1, divided by, 4, end fractionof a can of paint remaining. Th
Nadya [2.5K]
The height of the smaller can would need to be 12.8 cm.

First find the volume of the larger can of paint.  The volume of a cylinder is given by the formula
V=πr²h

Using the dimensions of the larger can, we have
V = 3.14(8²)(20) = 4019.2

Since he has 1/4 of this can, divide the volume by 4:
4019.2/4 = 1004.8

We will use this as the volume of the smaller can.  Substituting this in along with the radius of the smaller can (using the same volume formula), we have:
1004.8 = 3.14(5²)h
1004.8 = 78.5h

Divide both sides by 78.5:
1004.8/78.5 = 78.5h/78.5
12.8 = h
5 0
1 year ago
Find the area of the shaded portion in the equilateral triangle with sides 6. Show all work for full credit. (Hint: Assume that
Vadim26 [7]
So... if you notice the picture below

each circle, has their central angle at the vertex of the triangle
that simply means, 3 circles with a radius of 3, overlapping the triangle

now, the area in the middle, the shaded one, will be, the whole area of the triangle MINUS those 3 circle sectors

hmmmm each sector has 60°, that means, all three of them will then be 60+60+60 or 180°, so the area of those three sectors, can be combined into a 180° sector, well, hell, 180° is really half a circle

so.... the area of those three sectors of 60° each, all three combined, is the same area of half a circle with a radius of 3

so    \bf \textit{area of an equilateral triangle}\\\\&#10;A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\textit{length of one side}\\\\&#10;-----------------------------\\\\&#10;\textit{area of a circle}\\\\&#10;A=\pi r^2\qquad r=radius\\\\&#10;\textit{area of half a circle}\\\\&#10;A=\cfrac{\pi r^2}{2}\\\\&#10;-----------------------------\\\\

\bf \textit{now, let us use the side of 6, and radius of 3}&#10;\\\\\\&#10;&#10;\begin{array}{clclll}&#10;\cfrac{6^2\sqrt{3}}{4}&-&\cfrac{\pi 3^2}{2}\\&#10;\uparrow &&\uparrow \\&#10;triangle's&&semi-circle's&#10;\end{array}\impliedby \textit{area of shaded area}\\\\&#10;-----------------------------\\\\&#10;\boxed{\cfrac{36\sqrt{3}}{4}-\cfrac{9\pi }{2}}

you can, add the fractions if you want, or leave them like that, or get their difference by using their decimal format

8 0
2 years ago
Read 2 more answers
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