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Vaselesa [24]
2 years ago
11

Which expressions are equivalent to (2 Superscript 5 Baseline) Superscript negative 2? 2–10 and StartFraction 1 Over 20 EndFract

ion 2–10 and StartFraction 1 Over 1024 EndFraction 10–2 and StartFraction 1 Over 100 EndFraction 10–10 and StartFraction 1 Over 100 EndFraction
Mathematics
1 answer:
Serggg [28]2 years ago
4 0

Answer:

\frac{1}{2^{10}} \ and\ \frac{1}{1024}

Step-by-step explanation:

Given

(2^{5})^{-2}

Required

Find the equivalent;

To find the equivalent of the given expression, we make use of laws of indices;

Using the following law of indices;

(a^m)^n = a^{m*n}

So;

(2^{5})^{-2} becomes

(2^{5})^{-2} = 2^{5*-2}

(2^{5})^{-2} = 2^{-10} ------------ This is one equivalent

Solving further;

Using the following law of indices;

a^{-m} = \frac{1}{a^m}

So;

(2^{5})^{-2} = 2^{-10} becomes

(2^{5})^{-2} = \frac{1}{2^{10}}

2^10 = 1024

Hence;

(2^{5})^{-2} = \frac{1}{1024}

Conclusively; the equivalents of (2^{5})^{-2} are \frac{1}{2^{10}} \ and\ \frac{1}{1024}

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What is the length of ac?
leonid [27]

Answer:

Step-by-step explanation:

Given triangles are similar, so we setup a proportion  

(140-x)/81 = x/9

solving gives x = 14

AC = 140-x = 140-14 = 126

7 0
2 years ago
Read 2 more answers
A rectangular piece of plywood has a diagonal which measures two feet more than the width. The length of the plywood is twice th
icang [17]

Answer:

The length of the plywood's diagonal(to the nearest tenth) is, 3.6 and 1.4

Step-by-step explanation:

let l be the length and w be the width of the rectangle respectively;

Diagonal(D) of a rectangle is given by:

D = \sqrt{l^2+w^2}                              ......[1]

As per the given statement we have;

Diagonal(D) = width + 2

and

l = 2 \times w = 2w

Now, substitute these in  [1] we have;

\sqrt{(2w)^2+w^2} = w+5

Squaring both the sides we get;

4w^2+w^2 = (w+2)^2

5w^2 = w^2 + 4 + 4w

or

5w^2 -w^2 = 4w + 4 or

4w^2= 4w + 4

Simplify:

w^2-w-1 =0                         ......[2]

The quadratic equation is in the form  of ax^2+bx+c = 0

the solution is given by:  x = \frac{-b \pm\sqrt{b^2-4ac}}{2a}

On comparing with [1] we get

a= 1 , b = -1 and c = -1

Then the solution is:

w= \frac{-(-1) \pm\sqrt{(-1)^2-4(1)(-1)}}{2(1)}

w =\frac{1 \pm\sqrt{1+4}}{2} = \frac{1 \pm\sqrt{5}}{2}

Simplify:

w \approx 1.62 and w \approx -0.62

Then, the diagonal D = w+2

For w \approx 1.62

D = 1.62 +2 \approx 3.62

For w \approx -0.62

D =-0.62 +2 \approx 1.38

therefore, the length of the plywood's diagonal(to the nearest tenth) is, 3.6 and 1.4





5 0
2 years ago
The ballpark made a total of $15,000 from ticket sales at Wednesday's game. The ballpark charges $20 for each adult ticket and $
IRISSAK [1]
<h3>Answer:</h3>

equations

  • 20a +10c = 15000
  • c = 3a

solution

  • 300 adult
  • 900 children's
<h3>Step-by-step explanation:</h3>

Let "a" and "c" represent the numbers of adult and children's tickets sold, respectively. The problem statement tells us two relationships between these values:

... 20a +10c = 15000 . . . . . . total revenue from ticket sales

... c = 3a . . . . . . . . . . . . . . . . relationship between numbers of tickets sold

Using the expression for c, we can substitute into the first equation to get ...

... 20a +10(3a) = 15000

... 50a = 15000

... a = 15000/50 = 300 . . . . . adult tickets sold

... c = 3·300 = 900 . . . . . children's tickets sold

8 0
2 years ago
A car manufacturer is reducing the number of incidents with the transmission by issuing a voluntary recall. During week 10 of th
Digiron [165]

Answer:

f(x) = -5x + 250

Step-by-step explanation:

* Lets  explain how to solve the problem

- In week 10 the manufacturer fixed 200 cars

- In week 15, the manufacturer fixed 175 cars

- the reduction in the number of cars each week is linear

- The form of the linear equation is y = mx + c, where m is the slope of

 the line which represent the equation and c is the y-intercept

- The slope of the line m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

  where (x1 , y1) and (x2 , y2) are two points on the line

* Lets solve the problem

- Assume that the weeks' number is x and the cars' number is y

∴ (10 , 200) and (15 , 175) are two points on the line which represent

  the linear equation between the cars' numbers and the weeks

  numbers

∵ Point (x1 , y1) is (10 , 200) and point (x2 , y2) is (15 , 175)

∴ x1 = 10 , x2 = 15 and y1 = 200 and y2 = 175

- Use the rule of the slope above to find m

∴ m=\frac{175-200}{15-10}=\frac{-25}{5}=-5

- Substitute the value of x in the form of the linear equation above

∴ y = -5x + c

- To find c substitute x and y by one the coordinates of one of the

  two points

∵ x = 10 when y = 200

∴ 200 = -5(10) + c

∴ 200 = -50 + c

- Add 50 to both sides

∴ 250 = c

- Substitute the value of c by 250

∴ y = -5x + 250, where the number of cars seen each week is y and

  x is the number of the week

∵ f(x) = y

∴ f(x) = -5x + 250

7 0
2 years ago
Read 2 more answers
Jacinta buys 4 pounds of turkey and 2 pounds of ham. She pays a total of $30, and the turkey costs $1.50 less per pound than the
marissa [1.9K]

Given

jacinta buys 4 pounds of turkey and 2 pounds of ham & pays a total of $30, turkey costs $1.50 less per pound than the ham.

find out the combined cost of 1 pound of turkey and 1 pound of ham

To proof

As given in the question

jacinta buys 4 pounds of turkey and 2 pounds of ham

total pay by jacinta = $30

let us assume that the price of the ham = x

as given in the question

turkey costs $1.50 less per pound than the ham

turkey costs becomes = x - 1.50

then the equation becomes

30 = 4 (x - 1.50) + 2x

30 = 4x + 2x - 6

36 = 6x

x = 6

thus

ham cost per pound = $6

turkey cost per pound = 6 - 1.50

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Now find out

cost of 1 pound of turkey + 1 pound of ham = $ 6 + $ 4.5

                                                                       = $ 10.5

Hence proved





5 0
2 years ago
Read 2 more answers
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