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Zanzabum
2 years ago
5

The "hang time" of a football is the amount of time the football stays in the air after being kicked. Zara kicks a football, and

the height (in meters) of the football above the ground at ttt seconds is shown in the graph below. Complete the following sentences based on the graph of the function. This is the graph of a function. The hang time of the football is second(s). The football reaches its maximum height when t=\:t=t, equals second(s). The maximum height is about meter(s). (Round your answer to the nearest whole meter.) For ttt between t=0t=0t, equals, 0 and t=1.5t=1.5t, equals, 1, point, 5, the height is .
Mathematics
1 answer:
FrozenT [24]2 years ago
3 0

Answer:

Step-by-step explanation:

The graph is a nonlinear graph.

The hang time is 3 seconds.

The h- coordinate of the top of the bump is about 11 m, so the maximum height is 11 m after rounding to the nearest meter.

For t between 0 and 1.5, the height is increasing.

I hope this helps.  I found  it on Khan Academy.

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The data set below represents the ages of 36 executives. find the percentile that corresponds to an age of 4141 years old. 2828
solong [7]

Answer:

37th percentile.

Step-by-step explanation:

We have been given a data set that represents the ages of 36 executives. We are asked to find the percentile that corresponds to an age of 41 years.

28, 29, 29, 32, 32, 33, 34, 34, 34, 34, 37, 37, 38, 41, 41, 42, 45, 45, 47, 47, 47, 48, 50, 51, 53, 56, 56, 56, 61, 61, 62, 63, 64, 64, 65, 66.

Let us count the number of data points below and at 41.

We can see that the number of data points at and below 41 is 13.

We will use percentile formula to solve our given problem.

\text{Percentile rank of x}=\frac{\text{Number of values below x}}{\text{Total number of data points}}\times 100

\text{Percentile rank of 41}=\frac{13}{36}\times 100

\text{Percentile rank of 41}=0.361111\times 100

\text{Percentile rank of 41}=36.11\approx 37

Therefore, the percentile rank that corresponds to age of 41 years old is 37th percentile.  

8 0
2 years ago
Suppose that the regression equation y = 16.99 + 0.32 x1 + 0.41 x2 + 5.31 x3 predicts an adult’s height (y) given the individual
umka21 [38]

Answer:

Step-by-step explanation:

It is given that the regression equation

y = 16.99 + 0.32 x_1 + 0.41 x_2 + 5.31 x_3

predicts an adult’s height (y) given the individual’s mother’s height (x1), his or her father’s height (x2), and whether the individual is male (x3 = 1) or female (x3 = 0).

The coefficient of x1 = 0.32 represents the increase in height of the child due to one inch increase in mother.

Similarly coefficient of x2 = 0.42 represents the increase in height of the child due to one inch increase in father.

and coefficient of x3 = 5.31 represents the increase in height of the child due to being a male than a female.

8 0
2 years ago
Can you evaluate (g ○ f)(0)? Explain why or why not.
chubhunter [2.5K]

Answer:

No you can't because just like multiplication, you cant divide anything by zero.

Step-by-step explanation:

You must evaluate the function f first.  Division by 0 is undefined.

Therefore, The composition cannot be evaluated.

6 0
2 years ago
Read 2 more answers
In a cinema theatre, why do we normally not hear echoes even though the sounds are loud?<br>​
ikadub [295]

Answer:

An echo is formed as a result of reflection of the original sound which returns to the listener. You might have experienced Echo in an EMPTY ROOM but no echo is produced after the room is occupied. To avoid echo from being  produced the echo has to be absorbed. Echo in a cinema theatre is absorbed by the WALLS of the theatre.

They are not plain. The walls are corrugated or shaped to form tiny holes or empty spaces to ABSORB the ECHO. Modern Theatre's have ABSORBENT materials sticked to the walls of the theatre.

4 0
2 years ago
The weight of an object on Planet X is twice that of its weight on Earth and one third of its weight on Planet Y. If an object o
kari74 [83]
I’m confused on the wording but it might be either 600 or 33.333 (continues forever)
4 0
2 years ago
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