Answer:
This is the complete question:
for i ∈ {1,2,3,4,5,6} do beep
for j ∈ {1,2,3,4} do beep
for k ∈ {1,2,3} do
for l ∈ {1,2,3,4,5} do beep
for m ∈ {1,2,3,4} do beep
Explanation:
I will explain the algorithm line by line.
for i ∈ {1,2,3,4,5,6} do beep
This statement has a for loop and i variable that can take the values from 1 to 6. As there are 6 possible values for i so the beep statement gets executed 6 times in this for loop.
for j ∈ {1,2,3,4} do beep
This statement has a for loop and j variable that can take the values from 1 to 4. As there are 4 possible values for j so the beep statement gets executed 4 times in this for loop.
for k ∈ {1,2,3} do
for l ∈ {1,2,3,4,5} do beep
There are two statements here. The above statement has a for loop and k variable that can take the values from 1 to 3. As there are 3 possible values for k so the beep statement gets executed 3 times in this for loop. The below statement has a for loop and l variable that can take the values from 1 to 5. As there are 5 possible values for l so the beep statement gets executed 5 times in this for loop. However these statement work like an inner and outer loop where the outer loop is k and inner one is l which means 1 gets executed for each combination of values of k and l. As there are three values for k and 5 possible values for l so the combinations of values of k and l is 15 because 3 * 5 = 15. Hence the beep statement gets executed 15 times.
for m ∈ {1,2,3,4} do beep
This statement has a for loop and m variable that can take the values from 1 to 4. As there are 4 possible values for m so the beep statement gets executed 4 times in this for loop.
Now lets take the sum of all the above computed beeps.
for i = 6 beeps
for j = 4 beeps
for k and l possible combinations = 15 beeps
for m = 4 beeps
total beeps = 6 + 4 + 15 + 4 = 29 beeps
