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Maurinko [17]
2 years ago
11

Consider the following algorithm. for i ∈ {1,2,3,4,5,6} do ???? beep for j ∈ {1,2,3,4} do beep for k ∈ {1,2,3} do ???? for l ∈ {

1,2,3,4,5} do beep for m ∈ {1,2,3,4} do ???? ???? beep How many times does a beep statement get executed?
Computers and Technology
1 answer:
sukhopar [10]2 years ago
3 0

Answer:

This is the complete question:

for i ∈ {1,2,3,4,5,6} do  beep  

for j ∈ {1,2,3,4} do  beep  

for k ∈ {1,2,3} do

    for l ∈ {1,2,3,4,5} do beep  

for m ∈ {1,2,3,4} do  beep

Explanation:

I will explain the algorithm line by line.

for i ∈ {1,2,3,4,5,6} do  beep  

This statement has a for loop and i variable that can take the values from 1 to 6. As there are 6 possible values for i so the beep statement gets executed 6 times in this for loop.

for j ∈ {1,2,3,4} do  beep  

This statement has a for loop and j variable that can take the values from 1 to 4. As there are 4 possible values for j so the beep statement gets executed 4 times in this for loop.

for k ∈ {1,2,3} do

    for l ∈ {1,2,3,4,5} do beep  

There are two statements here. The above statement has a for loop and k variable that can take the values from 1 to 3. As there are 3 possible values for k so the beep statement gets executed 3 times in this for loop. The below statement has a for loop and l variable that can take the values from 1 to 5. As there are 5 possible values for l so the beep statement gets executed 5 times in this for loop. However these statement work like an inner and outer loop where the outer loop is k and inner one is l which means 1 gets executed for each combination of values of k and l. As there are three values for k and 5 possible values for l so the combinations of values of k and l is 15 because 3 * 5 = 15. Hence the beep statement gets executed 15 times.

for m ∈ {1,2,3,4} do  beep

This statement has a for loop and m variable that can take the values from 1 to 4. As there are 4 possible values for m so the beep statement gets executed 4 times in this for loop.

Now lets take the sum of all the above computed beeps.

for i = 6 beeps

for j = 4 beeps

for k and l possible combinations = 15 beeps

for m = 4 beeps

total beeps = 6 + 4 + 15 + 4 = 29 beeps

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D. You will not be able install the processor in the wrong motherboard.

<u>Explanation:</u>

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2. Pick socket combination is correct or not.

3. After upgrading the microprocessor, Brandon has to check whether voltage and cooling fans fit in the same space in the mother board.

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7 0
2 years ago
Describe a strategy for avoiding nested conditionals. Give your own example of a nested conditional that can be modified to beco
harina [27]

Answer:

One of the strategies to avoid nested conditional is to use logical expressions such as the use of AND & operator.

One strategy is to use an  interface class with a method. That method can be created to be used for a common functionality or purpose. This is also called strategy design pattern. You can move the chunk of conditional statement to that method. Then each class can implement that interface class and use that shared method according to their own required task by creating objects of sub classes and call that common method for any such object. This is called polymorphism.

Explanation:

Nested conditionals refers to the use of if or else if statement inside another if or else if statement or you can simply say a condition inside another condition. For example:

if( condition1) {  

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//executes when condition1  and condition2 evaluate to true

 }  else if(condition3) {

 //when condition1 is true and condition3 is true

} else {

 //condition1  is true but neither condition2 nor conditions3 are true

}  }

The deeply nested conditionals make the program difficult to understand or read if the nested conditionals are not indented properly. Also the debugging gets difficult when the program has a lot of nested conditionals.

So in order to avoid nested conditionals some strategies are used such as using a switch statement.

Here i will give an example of one of the strategies i have mentioned in the answer.

Using Logical Expressions:

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if(condition1 && condition2){  //this executes only when both condition1 and condition2 are true

} else if(condition1 && condition3) {

this executes only when both condition1 and condition3 are true

} else if(condition1 ){

//condition1  is true but neither condtion2 nor condtion3 are true  }

This can further be modified to one conditional as:

if(!condition3){

// when  condition1 and condition2 are true

}

else

// condition3 is true

Now lets take a simple example of deciding to go to school or not based on some conditions.

if (temperature< 40){

  if (busArrived=="yes")   {

      if (!sick)       {

          if (homework=="done")           {

              printf("Go to school.");

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      }     

  }

}

This uses nested conditionals. This can be changed to a single conditional using AND logical operator.

if ((temperature <40) && (busArrived=="yes") &&

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6 0
2 years ago
(Package Inheritance Hierarchy) Package-delivery services, such as FedEx®, DHL® and UPS®, offer a number of different shipping o
lys-0071 [83]

Answer:

Check the explanation

Explanation:

note: code is implemented as per the main method provided:

code:

using System;

public class Package

{

string senderName11;

string senderAddress1;

string senderCity1;

string senderState1;

string senderZip1;

string recipientName1;

string recipientAddress1;

string recipientCity1;

string recipientState1;

string recipientZip1;

decimal weight1;

decimal costPerOunce1;

public string SenderName11

{

get { return senderName11; }

set { senderName11 = value; }

}

public string SenderAddress1

{

get { return senderAddress1; }

set { senderAddress1 = value; }

}

public string SenderCity1

{

get { return senderCity1; }

set { senderCity1 = value; }

}

public string SenderState1

{

get { return senderState1; }

set { senderState1 = value; }

}

public string SenderZip1

{

get { return senderZip1;}

set { senderZip1 = value; }

}

public string RecipientName1

{

get { return recipientName1; }

set { recipientName1 = value; }

}

public string RecipientAddress1

{

get { return recipientAddress1; }

set { recipientAddress1 = value; }

}

public string RecipientCity1

{

get { return recipientCity1; }

set { recipientCity1 = value; }

}

public string RecipientState1

{

get { return recipientState1; }

set { recipientState1 = value; }

}

public string RecipientZip1

{

get { return recipientZip1; }

  set { recipientZip1 = value; }

}

public decimal Weight1

{

get { return weight1; }

set

{

if (value > 0)

weight1 = value;

else

Console.WriteLine("Weight1 can't be less tha zero");

}

}

public decimal CostPerOunce1

{

get { return costPerOunce1; }

set

{

if (value > 0)

costPerOunce1 = value;

else

Console.WriteLine("Cost per ounce can't be less than zero");

)

{

SenderName11 = senderName11;

SenderAddress1 = senderAddress1;

)

{

TwoDayDeliveryFee = twoDayDeliveryFee;

}

public override decimal CalculateCost()

{

return base.CalculateCost() + TwoDayDeliveryFee;

}

OvernightDeliveryFeePerOunce = overnightDeliveryFeePerOunce;

}

public override decimal CalculateCost()

{

return (CostPerOunce1 + OvernightDeliveryFeePerOunce) * Weight1;

}

}

class TestPackages

{

static void Main(string[] args)

{

Package regularPackage = new Package

(

"Peter Anderson",

"123 Main St, Ashville, NC 27111 ",

"Ashville",

"NC 27111",

"MN 55416",

"Mary Brown",

"456 Broad St Benson, NC 27222",

"St. Petersburg",

"Benson",

"NC 27222",

160M,

0.1M

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Console.WriteLine("\nRegular Package: ");

  Console.WriteLine(" Sender's Name: {0}",

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  Console.WriteLine(" Sender's Address: {0}",

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  Console.WriteLine(" Recipient's Name: {0}",

       regularPackage.RecipientName1);

  Console.WriteLine(" Recipient's Address: {0}",

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  Console.WriteLine(" Weight1: {0}"

, regularPackage.Weight1);

  Console.WriteLine(" Cost Per Ounce: {0:C}",

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  Console.WriteLine("Shipping Cost: {0:C}",

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Console.WriteLine(regularPackage.CalculateCost());

 

TwoDayPackage twoDayPackage = new TwoDayPackage

(

"Peter Anderson",

"123 Main St 123 Main St, Ashville, NC 27111",

"Ashville",

"NC 27111",

"MN 55416",

"Mary Brown",

"456 Broad St",

"St. Petersburg",

"Benson",

"NC 27222",

160M,

0.1M,

1.5M

);

  Console.WriteLine("\nTwo-Day Package: ");

  Console.WriteLine(" Sender's Name: {0}",

  twoDayPackage.SenderName11);

Console.WriteLine(" Sender's Address: {0}",

twoDayPackage.SenderAddress1);

  Console.WriteLine(" Recipient's Name: {0}",

   twoDayPackage.RecipientName1);

  Console.WriteLine(" Recipient's Address: {0}",

   twoDayPackage.RecipientAddress1);

  Console.WriteLine(" Weight1: {0}", twoDayPackage.Weight1);

  Console.WriteLine(" Cost Per Ounce: {0:C}",

   twoDayPackage.CostPerOunce1);

  Console.WriteLine(" Flat Fee: {0:C}",

   twoDayPackage.Weight1);

  Console.WriteLine(" Shipping Cost: {0:C}",

   twoDayPackage.CalculateCost());

OvernightPackage overnightPackage = new OvernightPackage

(

"Peter Anderson",

"123 Main St 123 Main St, Ashville, NC 27111",

"Ashville",

"NC 27111",

"MN 55416",

"Mary Brown",

"456 Broad St Benson, NC 27222",

"St. Petersburg",

"Benson",

"NC 27222",

160M,

0.1M,

1.5M

);

Console.WriteLine("\nOvernight Package: ");

  Console.WriteLine(" Sender's Name: {0}",

   overnightPackage.SenderName11);

  Console.WriteLine(" Sender's Address: {0}",

   overnightPackage.SenderAddress1);

  Console.WriteLine(" Recipient's Name: {0}",

   overnightPackage.RecipientName1);

  Console.WriteLine(" Recipient's Address: {0}",

   overnightPackage.RecipientAddress1);

  Console.WriteLine(" Weight1: {0}",

   overnightPackage.Weight1);

  Console.WriteLine(" Cost Per Ounce: {0:C}",

   overnightPackage.CostPerOunce1);

  Console.WriteLine(" Additional Cost Per Ounce: {0:C}",

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  Console.WriteLine(" Shipping Cost: {0:C}",

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Console.WriteLine(overnightPackage.CalculateCost()); Console.ReadKey();

}

}

The Result can be seen below:

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geniusboy [140]

Answer:

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Explanation:

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This system limits the IPv4 protocol to 4,000 million different addresses, a figure that in the eighties seemed sufficient but that in practice has been scarce due to the revolution of mobile devices and the impending development of the Internet of Things ( IoT) that will trigger the number of devices connected to the network.

So, there are no additional components that can be added to the IPv4 protocol to improve its utility, since the world is running out of IPv4 addresses and is being replaced by IPv6.

Hope this helps!

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