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Afina-wow [57]
2 years ago
13

Ashley is doing some math exercises on a website called Khon Academy. In Khon Academy, you have to get at least 70% of the probl

ems in an exercise right in order to gain proficiency. So far, Ashley has answered correctly 3 out of 7 times. Suppose she answers all of the following q questions correctly and gains proficiency in the exercise. Write an inequality in terms of q that models the situation.
Mathematics
2 answers:
Flauer [41]2 years ago
8 0

Answer:

q>=2

Step-by-step explanation:

if she has 3 out of 7 correct she only needs 2 more right. 70% of 7 needs to be 5 or more  5-3=2

iragen [17]2 years ago
8 0

Answer:

I believe the answer is q>=2.

Step-by-step explanation:

Hope this is correct, thank you!!!!

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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do
vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107

Then,

P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007

c) In this case, the distribution is B(1200,0.01)

P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366

5 0
2 years ago
Based on a study from the Chronicles of Flippin'' Awesomeness, the probability that Napoleon and Pedro make it to their first pe
muminat

Answer:

15.25% probability that Napoleon and Pedro catch the bus and make it to their first period class on time

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, we have that:

Event A: Both Napoleon and Pedro catch the bus, so P(A) = 0.25.

Event B: Making to their first period class on time.

However, the probability that they make it to their first period class on time, given that they catch the bus is 0.61.

This means that P(B|A) = 0.61

What is the probability that Napoleon and Pedro catch the bus and make it to their first period class on time

P(B|A) = \frac{P(A \cap B)}{P(A)}

0.61 = \frac{P(A \cap B)}{0.25}

P(A \cap B) = 0.61*0.25

P(A \cap B) = 0.1525

15.25% probability that Napoleon and Pedro catch the bus and make it to their first period class on time

8 0
2 years ago
The process of using the same or similar experimental units for all treatments is called:______
Charra [1.4K]

Answer:

replicating

Step-by-step explanation:

3 0
2 years ago
For an outdoor track meet to be cancelled, the temperature, t, outside must be colder than 35 degrees. Complete the following in
qwelly [4]

Answer: I'm pretty sure it would be -7º Celcius for it to be cancelled. Hope it helped!

7 0
2 years ago
Read 2 more answers
All of the following expressions are equal to N except _____. |−N| −(−N) |N| −N
Maksim231197 [3]

Answer:

D. -N

Step-by-step explanation:

Our four given expressions are:

A. |-N|

B. -(-N)

C. |N|

D. -N

The | | symbols represent absolute value, which is the distance from the value within the two lines and 0; essentially since it measures distance, absolute value always outputs a positive value.

In choice A, we have |-N|, which means the distance between -N and 0. Well, the distance will simply be N, which is equal to N. Eliminate A.

In choice B, we have -(-N). Double negatives signal that they will cancel out to become positive, so -(-N) = N. Eliminate B.

In choice C, we have |N|, which means the distance between N and 0. This is clearly just N, so eliminate C.

In choice D, we have -N, which denotes "negative N". Clearly, "negative N" (-N) is not the same as "positive N" (N), so D is the answer.

<em>~ an aesthetics lover</em>

3 0
2 years ago
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