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2 years ago

All of the following expressions are equal to N except _____. |−N| −(−N) |N| −N

Mathematics

2 answers:

Dmitriy789 [7]2 years ago

7 0

Answer:

-N

Step-by-step explanation:

Maksim231197 [3]2 years ago

3 0

Answer:

D. -N

Step-by-step explanation:

Our four given expressions are:

A. |-N|

B. -(-N)

C. |N|

D. -N

The | | symbols represent absolute value, which is the distance from the value within the two lines and 0; essentially since it measures distance, absolute value always outputs a positive value.

In choice A, we have |-N|, which means the distance between -N and 0. Well, the distance will simply be N, which is equal to N. Eliminate A.

In choice B, we have -(-N). Double negatives signal that they will cancel out to become positive, so -(-N) = N. Eliminate B.

In choice C, we have |N|, which means the distance between N and 0. This is clearly just N, so eliminate C.

In choice D, we have -N, which denotes "negative N". Clearly, "negative N" (-N) is not the same as "positive N" (N), so D is the answer.

<em>~ an aesthetics lover</em>

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Let e1= 1 0 and e2= 0 1 , y1= 4 5 , and y2= −2 7 , and let T: ℝ2→ℝ2 be a linear transformation that maps e1 into y1 and maps

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Answer:

The image of $\left[\begin{array}{c}4&-4\end{array}\right]$ through T is $\left[\begin{array}{c}24&-8\end{array}\right]$

Step-by-step explanation:

We know that $T:$ $IR^{2}$ → $IR^{2}$ is a linear transformation that maps $e_{1}$ into $y_{1}$ ⇒

$T(e_{1})=y_{1}$

And also maps $e_{2}$ into $y_{2}$ ⇒

$T(e_{2})=y_{2}$

We need to find the image of the vector $\left[\begin{array}{c}4&-4\end{array}\right]$

We know that exists a matrix A from $IR^{2x2}$ (because of how T was defined) such that :

$T(x)=Ax$ for all x ∈ $IR^{2}$

We can find the matrix A by applying T to a base of the domain ( $IR^{2}$ ).

Notice that we have that data :

$B_{IR^{2}}=$ { $e_{1},e_{2}$ }

Being $B_{IR^{2}}$ the cannonic base of $IR^{2}$

The following step is to put the images from the vectors of the base into the columns of the new matrix A :

$T(\left[\begin{array}{c}1&0\end{array}\right])=\left[\begin{array}{c}4&5\end{array}\right]$ (Data of the problem)

$T(\left[\begin{array}{c}0&1\end{array}\right])=\left[\begin{array}{c}-2&7\end{array}\right]$ (Data of the problem)

Writing the matrix A :

$A=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]$

Now with the matrix A we can find the image of $\left[\begin{array}{c}4&-4\\\end{array}\right]$ such as :

$T(x)=Ax$ ⇒

$T(\left[\begin{array}{c}4&-4\end{array}\right])=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]\left[\begin{array}{c}4&-4\end{array}\right]=\left[\begin{array}{c}24&-8\end{array}\right]$

We found out that the image of $\left[\begin{array}{c}4&-4\end{array}\right]$ through T is the vector $\left[\begin{array}{c}24&-8\end{array}\right]$

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2 years ago

Which equation represents a proportional relationship that has a constant of proportionality equal to –10? y = x minus 10 y = x/

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Answer:

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Step-by-step explanation:

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Which could be the dimensions of a rectangular prism whose surface area is greater than 140 square feet? Select three options,

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Answer:

These are the rectangular prisms that have a surface area greater than 140 square feet

6 feet by 5 feet by 4 feet

7 feet by 6 feet by 4 feet

8 feet by 3 feet by 7 feet

Step-by-step explanation:

The formula to find the surface area of a rectangular prism is SA=2(wl+hl+hw)

All you have to do is go through all the options given to you to figure out which retangular prisms have a surface area greater than 140 square feet.

6 feet by 2 feet by 3 feet

SA = 2((2)(6)+(3)(6)+(3)(2))

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6 feet by 5 feet by 4 feet

SA = 2((6)(5) + (4)(5) + (4)(6))

SA = 2(30 + 20 + 24)

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7 feet by 6 feet by 4 feet

SA = 2((7)(6) + (4)(6) + (4)(7))

SA = 2(42 + 24 + 28)

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8 feet by 3 feet by 7 feet

SA = 2((8)(3)+(7)(3)+(7)(8))

SA = 2(24 + 21 + 56)

SA = 2(101)

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8 feet by 4 feet by 3 feet

SA = 2((8)(4)+(3)(4)+(3)(8))

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