Ask question

Ask question

All categories

2 years ago

10

A company manufactures a 14-ounce box of cereal. Boxes are randomly weighed to ensure the correct amount. If the discrepancy in

weight is more than 0.25 ounces, the production is stopped.
Which function could represent this situation? Ede

1 answer:

Stolb23 [73]2 years ago

8 0

Answer:

Answer is B on Edge

F(x)=14-x

Step-by-step explanation:

You might be interested in

A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave

erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, $L$ = 120 cm

Its wavelength $\lambda_1$ = 480 cm

$\lambda_2$ = 160 cm and $\lambda_3$ = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

The fundamental wavelength of a pipe which is open at both ends is 2L.
The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ $4L=4(120)=480\ cm$

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒ $\lambda_2=\frac{4L}{3}$ ⇒ $\lambda_3=\frac{4L}{5}$

⇒ $\lambda_2=\frac{4(120)}{3}$ ⇒ $\lambda_3=\frac{4(120)}{5}$

⇒ $\lambda_2=\frac{480}{3}$ ⇒ $\lambda_3=\frac{480}{5}$

⇒ $\lambda_2=160\ cm$ ⇒ $\lambda_3=96\ cm$

So the pipe is open at one end and closed at one end .

6 0

2 years ago

Which statement is true about the discontinuities of the function f(x)?

Tema [17]

Answer:

There are asymptotes at x = three-halves and x = negative one-third.

Step-by-step explanation:

f(x) = (x + 1)/ (6x^2 - 7x - 3)

= (x + 1)( / (6x^2 + 2x - 9x - 3)

= (x + 1) / (2x(3x + 1) - 3(3x + 1))

= (x + 1) / (2x - 3)(3x + 1)

Now x = 3/2 and x = -1/3 both make te denominator zero so these are both asymptotes.

6 0

2 years ago

Read 2 more answers

If f(x) = 53 - 2x, then f(-3) =

zheka24 [161]

Substitute -3 for x in the expression

f(x)= 53 - 2x

f(-3)= 53 - 2(-3)
multiply -2 * -3

f(-3)= 53 + 6
add

f(-3)= 59

ANSWER: f(-3)= 59

Hope this helps! :)

4 0

2 years ago

In the figure above, two line segments in the x-y plane form a right triangle with the x-axis. What is the area of the triangle

Juli2301 [7.4K]

A = (1/2) * b * h
The base is 10; the x-value going from 0 to 10.
The perpendicular height is 2; the y-value going from 0 to 2
A = (1/2) * 10 * 2
A = 10 units ^2

7 0

2 years ago

Find the inverse of y=x2-10x

anzhelika [568]

<span>this is pretty hard but here is your answer
</span>

y = x^2 - 10x + 25 - 25

<span> y = (x-5)^2 - 25 </span>

<span> y+25 = (x-5)^2 </span>

<span> x-5 = +/-sqrt(y+25) </span>

<span> And you get TWO inverses: </span>

<span> x = 5 + sqrt(y+25), for x>=5 </span>

<span> x = 5 - sqrt(y+25), for x<=5</span>

5 0

2 years ago

Read 2 more answers