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sveta [45]
2 years ago
11

Which triangle results from a reflection across the line x = 1?

Mathematics
2 answers:
Nataly_w [17]2 years ago
7 0

Answer:

Correct answer is option D.

Step-by-step explanation:

Given that \triangle ABC in the image 1 attached.

If we have a look at the image attached, the coordinates are:

A(1,1)\\B(2,5)\ and\\C(4,1)

<em>To find reflection</em> of a point across any line, the distance of points from the line must be same.

Point A(1,1) lies on the line x = 1, so its reflection A' will be at the same point A'(1,1).

Point C(2,5) is at a distance 1 from x = 1 on right side, so C' will be 1 distance on the left side of x = 1 i.e. 1 will be subtracted from its x coordinate.

i.e. C'(1 - 1, 5)

C'(0, 5)

Point B(4, 1) is at a distance 3 from x = 1 on right side, so B' will be 3 distance on the left side of x = 1 i.e. 3 will be subtracted from its x coordinate.

i.e. B'(1 - 3, 1)

B'(-2, 1)

<em>When we plot the above point A', B' and C', we get the option D as correct.</em>

Rainbow [258]2 years ago
4 0

Answer:

D

Step-by-step explanation:

Just took it on A P E X

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Tems11 [23]

Answer:

The amount that will go towards the balance is 385.71.

Step-by-step explanation:

The information provided is:

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First compute the Equated monthly installments (EMI) as follows:

EMI=\frac{P\times r\times (1+r)^{n}}{(1+r)^{n}-1} \\=\frac{15000\times0.0045\times(1+0.0045)^{36}}{(1+0.0045)^{36}-1} \\=\frac{79.3125}{0.175}\\=453.21

Now compute the interest as follows:

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The amount that will go towards the balance is,

Amount towards the balance = EMI - Interest  

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Thus, the amount that will go towards the balance is 385.71.

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Hello,

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After a number of complaints about its tech assistance, a computer manufacturer examined samples of calls to determine the frequ
icang [17]

Answer:

a) Upper Control Limit = 0.10

   Lower Control Limit = 0.01

b) The tech assistance process is stable and in control.

Step-by-step explanation:

Given - After a number of complaints about its tech assistance, a

            computer manufacturer examined samples of calls to determine

            the frequency of wrong advice given to callers. Each sample

            consisted of 100 calls.

SAMPLE             1   2   3   4   5   6   7   8   9  10 11 12 13 14 15 16

Number of errors 5  3   5   7   4   6   8   4   5    9   3   4   5   6   6   7

To find - a. Determine 95 percent limits.

              b. Is the tech assistance process stable (i.e., in control)

Proof -

z = 95% confidence interval

  = 1.96

⇒z = 1.96

Proportion of defects,P = total defectives/total observations

                                     = 0.0544

⇒P = 0.0544

Now,

Q = 1-P

   = 0.9456

⇒Q = 0.9456

Now,

Average sample size, N = 100

Standard deviation = \sqrt{\frac{P.Q}{N} }

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Now,

Upper Control Limit = P + z(Standard deviation)

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⇒Upper Control Limit = 0.0988 ≈ 0.10

And

Lower Control Limit = P - z(Standard deviation )

       = 0.0099

⇒Lower Control Limit = 0.0099 ≈ 0.01

∴ we get

Upper Control Limit = 0.10

Lower Control Limit = 0.01

b.)

Now,

it is clear that the fraction defective values are wit in upper an lower control limits.

So, The tech assistance process is stable and in control.

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2 years ago
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