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dedylja [7]
2 years ago
12

Point X is 34m due east of a point Y the bearings of a flagpole from and Y are N18°W and N40°E respectively. Calculate the dista

nce of the flagpole from Y

Mathematics
1 answer:
julia-pushkina [17]2 years ago
6 0

Answer:

Step-by-step explanation:

The diagram representing the scenario is shown in the attached photo. Triangle FXY is formed with F representing the flagpole.

The sum of the angles in a triangle is 180

Angle F = 180 - (50 + 72) = 58°

We want to determine FY, the distance of the flagpole from Y. We would apply the sine rule which is expressed as

a/Sine A = b/SinB = c/SinC

Likening it to the given triangle, it becomes

FY/Sin72 = 34/Sin 58

Cross multiplying, it becomes

FYSin58 = 34Sin72

FY = 34Sin72/Sin58

FY = 34 × 0.951/0.848

FY = 38.13m

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In the diagram, the distance between the microphones is 6 feet. This is 3 times the distance d from each microphone to the sound
Readme [11.4K]

Answer:

3d = 6

Step-by-step explanation:

since the distance is 6 feet, 3 times the distance (d) would give you the equation, 3d= 6.

:)

7 0
2 years ago
Evaluate u + xy, for u = 20, x = 9, and y = 8. 188 37 232 92
givi [52]

let's see

u + xy

Plug in numbers that you know:

20 + 9 * 8

20 + 72

92

8 0
2 years ago
Read 2 more answers
Supervisor: "I am giving you 10 business days to make a 4% improvement on your average quality score. Your current average quali
kobusy [5.1K]

"Then I will need an average quality score of <u>3.28</u>  to meet 85.28 goal."

<u>Step-by-step explanation</u>:

  • current average quality score = 82
  • improvement on average quality score = 4% of 82

⇒ (4/100)\times82

⇒ 82/25

⇒ 3.28

The improved average quality score = 82+3.28 = 85.28

The employee needs an average quality score of 3.28 to meet the goal of 85.28

5 0
2 years ago
A rectangular board is 1.8 meters long and 1.25 meters wide. What is the area of the board in square millimeters? Do not round y
lilavasa [31]

Answer:

2250000 mm^2 or 2.25 m^2

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7 0
1 year ago
A four year old is going to spin around with his arms stretched out 100 times. From past experience, his father knows it takes a
Sati [7]

Answer:

P(X \geq0.55) \leq 0.22

Step-by-step explanation:

Using central Limit Theorem (CLT), The sum of 100 random variables;

Y=X_1+X_2+...+X_{100} is approximately normally distributed with

Y ~ N (100 × \frac{1}{3^2} ) = N ( 50, \frac{100}{9} )

The approximate probability that it will take this child over 55 seconds to complete spinning can be determined as follows;

N ( 50, \frac{100}{9} )

P(Y>55) =P(Z>\frac{55-50}{10/3})

P(Y>55) =P(Z>1.5)

P(Y>55) =\phi (-1.5)

P(Y>55) =0.0668

Using Chebyshev's inequality:

P(|X-\mu\geq K)\leq \frac{\sigma^2}{K^2}

Let assume that X has a symmetric distribution:

Then:

2P(X-\mu\geq K)\leq) \frac{\sigma^2}{K^2}

2P(X \geq \mu+K)\leq) \frac{\sigma^2}{K^2}

2P(X\geq0.5+0.05)\leq \frac{\frac{1}{\frac{3^2}{100} } }{0.05^2}               where: (\sigma^2 = \frac{1}{3^2/100})

P(X \geq0.55) \leq 0.22

6 0
2 years ago
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