Answer:
In order for it to benefit his father to buy the pass Seth have to attend the movies for 11 times.
Step-by-step explanation:
Given:
Cost of movie pass = $40
Cost per matinees with pass = $1.00
Cost per matinees without pass = $3.50
To Find:
Number of times must Seth attend in order for it to benefit his father to buy the pass = ?
Solution:
Let x be the number of times he wants to visit
To profit his father
The number of visits without pass = the number of visits with passin the cost of $3.50
Then, without pass if he visits for x times then the cost will be = 3.50x
Also with pass, the number of times he can visit the pass = 
then
x = 11.42
x = 11 (approx)
Answer: 2.7 hours
Step-by-step explanation:
Hi, to answer this question we simply have to calculate the amount of time that takes making one batch of dinner rolls, by adding the individual times of, kneading, resting and baking.
Mathematically speaking
0.7 hours +1.6 hours +0.4 hours = 2.7 hours
It takes 2.7 hours to make each batch of dinner rolls.
So we know $8.50 per hour
One-time fee of $15 for uniform
x hours per week
y=8.5x-15
Answer:
<h3>AC=96 units.</h3>
Step-by-step explanation:
We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.
, and CE=6x .
<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>
Therefore, AE = EC.
Plugging expressions for AE and EC, we get
Subtracting 6x from both sides, we get
Factoriong quadratic by product sum rule.
We need to find the factors of -16 that add upto -6.
-16 has factors -8 and +2 that add upto -6.
Therefore, factor of quadratic is (x-8)(x+2)=0
Setting each factor equal to 0 and solve for x.
x-8=0 => x=8
x+2=0 => x=-2.
We can't take x=-2 as it's a negative number.
Therefore, plugging x=8 in EC =6x, we get
EC = 6(8) = 48.
<h3>AC = AE + EC = 48+48 =96 units.</h3>
Answer:
that would be 16 dollars
Step-by-step explanation:
80.00 multiplied by .2 equals 16
