Answer
The answer and procedures of the exercise are attached in the following archives.
Consider the excel document where the source of the results is plotted.
Explanation
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
75 I think not 100% but that makes Sense
Answer:
- $104.50
- $67.50
- $65.50
- $77.50
- $56.50
Explanation:
the income tax to withhold from the biweekly wages are :
- <u> </u><u>Karen Overton (single, 0 allowances), $900 wages</u>
=$34.90 + ($900 - 436) x 15%
= $104.50
- <u> Nancy Haller (married, 4 allowances), $1,000 wages </u>
=($1000 - 325 ) x 10%
= $67.50
- <u>Alan Glasgow (married, 1 allowance), $980 wages </u>
=($980 - 325 ) x 10%
= $65.50
- <u>Joseph Kerr (single, 4 allowances), $720 wages </u>
= $34.90 + ($720 - $436) x 15%
= $77.50
- <u> </u><u>Ginni Lorenz (single, 1 allowance), $580 wages</u>
= $34.90 + ($580 - $436) x 15%
= $56.50
Answer : The p-value of 0.0743 is greater than alpha at 0.05; so we fail to reject the null hypothesis and conclude that there is no significant difference in the number of unique users before and after a change in policy.
In this question, the manager wants to know if the number of users has changed.
So, the null and alternate hypotheses are:
Null Hypothesis: 
Alternate Hypothesis :
Type of test : Two-tailed test
The level of significance is 95%
We can calculate alpha (α) as follows:


The p value = 0.0743.
We use the following rules to arrive at a conclusion when p-values and alpha is given:
If
, reject the null hypothesis
If
, we don't reject the null hypothesis.
Since the p-value is greater than alpha, we don't reject the null hypothesis.
D because a discount is an upfront guaranteed incentive