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Alinara [238K]
2 years ago
15

An insurance company reported that, on average, claims for a certain medical procedure are $942. An independent organization con

structed a 95% confidence interval of ($930 , $950) for the average amount claimed for the particular medical procedure. What conclusion best evaluates the truthfulness of the number reported by the insurance company?
Mathematics
1 answer:
kirza4 [7]2 years ago
7 0

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

An insurance company reported that, on average claims for a certain medical procedure are $942. an independent organization constructed a 95% confidence interval of ($930, $950) for the average amount claimed for the particular medical procedure. what conclusion best evaluates the truthfulness of the number reported by the insurance company?

a) with 95% certainty, the average claim for this medical procedure is $942.

b) with 95% certainty, the average claim for this medical procedure is not $942.

c) the confidence interval is consistent with an average claim of $942 for this medical procedure

Solution:

Confidence interval is used to express how confident we are that the population parameter that we are looking for is contained in a range of given values. Looking at the given confident interval, the lower limit is $930 and the upper limit is $950. We can see that the population mean, $942 lies within these values. The correct option would be

c) the confidence interval is consistent with an average claim of $942 for this medical procedure

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Answer:

(1,0)

Step-by-step explanation:

The given functions are:

f(x) = log₂x

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g(x) = log₁₀x

We know that logarithm of 1 is always zero.

This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1

Therefore the point the graphs of f and g have in common is (1,0)

3 0
1 year ago
The luxor hotel in las vegas is a square base pyramid that is 646 feet wide at the base and 350 feet tall. if the outer walls of
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We must calculate the lateral area which is given by:
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4 0
2 years ago
In the 2009-2010 school year in country A, there were 92,000 foreign students from country B. This number I 23% more than the nu
max2010maxim [7]

Answer:

\approx74796

Step-by-step explanation:

GIVEN: In the 2009-10 school year in country A, there were 92,000 foreign students from country B. This number is 23\% more than the number of students from country C.

TO FIND: How many foreign students were from country C.

SOLUTION:

Total foreign students from country B =92000

let the foreign students from country C be x

As the students from country B is 23\% more than the country C

Students from country B

92000=\frac{123}{100}x

x=\frac{9200000}{123}

x\approx74796

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8 0
2 years ago
Frank left his house at 7 a.m. and drove to the airport at a speed of 50 mph. Lance left his house at 6 a.m. and drove to the sa
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Answer:

10 AM

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3 0
1 year ago
The null hypothesis says that a sprinter's reaction time follows a normal distribution with mean at most 0.150 seconds. Six meas
kkurt [141]

Answer:

The P-value is 0.0353.

Step-by-step explanation:

We are given the six measurements of a sprinter's reaction time show below;

X = 0.152, 0.154, 0.166, 0.147, 0.161, and 0.159 seconds.

Let \mu = <u><em>mean sprinter's reaction time</em></u>

So, Null Hypothesis, H_0 : \mu \leq 0.150 seconds    {means that the mean sprinter's reaction time is at most 0.150 seconds}

Alternate Hypothesis, H_A : \mu > 0.150 seconds    {means that the mean sprinter's reaction time is more than 0.150 seconds}

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            n = sample of measurements = 6

So, <u><em>the test statistics</em></u> =  \frac{0.1565-0.150}{\frac{0.0068}{\sqrt{6} } }  ~  t_5

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P-value = P( > 2.341) = 0.0353.

{Interpolating between the critical values at 5% and 2.5% significance level}

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