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grandymaker [24]
2 years ago
7

A tiling company completes two jobs. The first job has $1200 in labor expenses for 40 hours worked, while the second job has $15

60 in labor expenses for 52 hours worked. The relationship between the labor expenses and the hours worked is linear. Which equation can be used to calculate the y-intercept of the linear equation?
Mathematics
1 answer:
Luba_88 [7]2 years ago
3 0

Answer:

52 days

Step-by-step explanation:

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An individual is hosting a cookout for the kick ball team. The individual wants to have two hot dogs for each guest, and 6 extra
hoa [83]

Answer:

Option 2) y = 26    

Step-by-step explanation:

We are given the following in the question:

The individual wants to have two hot dogs for each guest, and 6 extra hot logs in case some teammates bring friends.

Thus, the dependent variable is the number of hot dogs.

\text{y: Number of hot dogs}

The independent variable is the number of teammates.

\text{x: Number of teammates}}

Thus, the linear relation between the dependent and the independent variable is given as:

y(x) = 2x + 6

We have to find the value of dependent variable when independent variable is 10

For x = 10

y(10) = 2(10) + 6 = 26

Thus, the correct answer is

Option 2) y = 26

3 0
2 years ago
The diagram below shows scalene triangle WXY. The measure of WXY is 71 degree.
Leya [2.2K]

Answer:

A  AND D

Step-by-step explanation:

5 0
2 years ago
Ayuda es para mañana El estudiante 1 y el estudiante 2 están a 53 metros, uno del otro. El estudiante 1, desde su posición, ve u
hram777 [196]

Answer:

La opción correcta es;

Estudiante 2, ya que está aproximadamente a 32,39 metros de distancia

Step-by-step explanation:

Los parámetros dados son;

La distancia entre los dos estudiantes = 53 metros

El ángulo medido entre la línea del Estudiante 1 a la caja fuerte y el Estudiante 1 y el Estudiante 2 = 37 °

El ángulo medido entre la línea del Estudiante 2 a la caja fuerte y el Estudiante 2 y el Estudiante 1 = 43 °

Dado que los dos estudiantes y la caja fuerte forman los vértices de un triángulo, tenemos;

Sea θ el ángulo del triángulo opuesto a la distancia entre los dos estudiantes

Por lo tanto;

θ + 43 ° + 37 ° = 180 ° (teorema de suma de ángulos)

θ = 180 ° - (43 ° + 37 °) = 100 °

Por regla del seno, tenemos;

a / (sin (A) = b / sin (B)

Por lo tanto;

53 / (sin (100 °)) = b / (sin (37 °)) = c / (sin (43 °))

Lo que da;

b = (sin (37 °)) × 53 / (sin (100 °)) = 32,39 metros

c = (sin (43 grados)) × 53 / (sin (100 grados)) = 36,7 metros

Por lo tanto, el Estudiante 2 está más cerca, ya que está aproximadamente a 32,39 metros de distancia.

6 0
2 years ago
The weight of corn chips dispensed into a 14-ounce bag by the dispensing machine has been identified as possessing a normal dist
mamaluj [8]
The probability that a normally distributed dataset with a mean, μ, and statndard deviation, σ, exceeds a value x, is given by

P(X\ \textgreater \ x)=1-P(X\ \textless \ x)=1-P\left(z\ \textless \  \frac{x-\mu}{\frac{\sigma}{\sqrt{n}}} \right)

Given that t<span>he weight of corn chips dispensed into a 14-ounce bag by the dispensing machine is a normal distribution with a mean of 14.5 ounces and a standard deviation of 0.2 ounce.

</span>If <span>100 bags of chips are randomly selected the probability that the mean weight of these 100 bags exceeds 14.6 ounces is given by

P(X\ \textgreater \ 14.6)=1-P\left(z\ \textless \  \frac{14.6-14.5}{\frac{0.2}{\sqrt{100}}} \right) \\  \\ =1-P\left(z\ \textless \  \frac{0.1}{\frac{0.2}{10}} \right)=1-P\left(z\ \textless \  \frac{0.1}{0.02} \right) \\  \\ =1-P(z\ \textless \ 5)=1-1=0

Therefore, the probability that </span><span>the mean weight of these 100 bags exceeds 14.6 ounces is</span> 0.

7 0
2 years ago
Zucchini weights are approximately normally distributed with mean 08 pound and standard deviation 0.25 pound. Which of the follo
marissa [1.9K]

Answer:

The correct option is  A

Step-by-step explanation:

From the question we are told that

   The  mean is  \mu  =  0.8 \ pounds

    The standard deviation is  \sigma =  0.25  \  pounds

Generally the the probability that a  randomly selected zucchini will weigh between 0 55 pound and 13 pounds is mathematically represented as

       P(0.55 <  X  <  1.3)  =  P(\frac{0.55 - 0.8}{ 0.25} <  \frac{X -  \mu}{\sigma }  <  \frac{1.3 - 0.8}{0.25})

=>    P(0.55 <  X  <  1.3)  =  P( -1 <  Z  <  2 )

So looking the option of normal curves given in the question we see that it is option A that matches our interval  

8 0
2 years ago
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