Question

A rectangular solid with a square base has a volume of 5832 cubic inches. (Let x represent the length of the sides of the square base and let y represent the height.)
(a) Determine the dimensions that yield the minimum surface area.
(b) Find the minimum surface area.

Answer 1

Answer:

a) 18 in x 18 in x 18 in

b) $S = 1944\ in2$

Step-by-step explanation:

a) Let's call 's' the side of the square base and 'h' the height of the solid.

The surface area is given by the equation:

$S = 2s^2 + 4sh$

The volume of the solid is given by the equation:

$V = s^2h = 5832$

From the volume equation, we have that:

$h = 5832/s^2$

Then, using this value of h in the surface area equation, we have:

$S = 2s^2 + 4s(5832/s^2)$

$S = 2s^2 + 23328/s$

To find the side length that gives the minimum surface area, we can find where the derivative of S in relation to s is zero:

$dS/ds = 4s - 23328/s^2 = 0$

$4s = 23328/s^2$

$4s^3 = 23328$

$s^3 = 23328/4 = 5832$

$s = 18\ inches$

The height of the solid is:

$h = 5832/(18)^2 = 18\ inches$

b) The minimum surface area is:

$S = 2(18)^2 + 4(18)(18)$

$S = 1944\ in2$