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lora16 [44]
2 years ago
15

2. Company A packages roofing nails in boxes that are normally distributed with a mean of 276 nails and a standard deviation of

5.8 nails. Company B packages roofing nails in boxes that are normally distributed with a mean of 252 nails and a standard deviation of 3.4 nails. Which company is more likely to produce a box of 260 roofing nails? Explain your answer using z-scores.
Mathematics
1 answer:
Natali5045456 [20]2 years ago
6 0

Answer:

Company B

Step-by-step explanation:

We would use z score formula

z = (x - μ) / σ

x = raw score

μ = mean

σ = Standard deviation

let x = 260 with the mean μ1 = 276 and standard deviation σ = 5.8

let x = 260 with the mean μ2 = 252 and standard deviation σ = 3.4

z1 = (x- μ1) / σ = (260- 276) / 5.8 = -2.7586206897 = -2.76

z2 = (x2 - μ) / σ = (260 -252) / 3.4= 2.3529411765 = 2.35

Comparing the two z scores, we can see that company B has the probability of producing 260 nails because it has a z score of 2.35 compared to company A with a z score of -2.76.

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irga5000 [103]

Answer:

The correct option is;

Use a scale factor of 2

Step-by-step explanation:

The parameters given are;

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We note that the length of side AB in polygon ABCD = √((5 -1)² + (-6 - (-6))²) = 4

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AB/A''B'' = 4/2 = 2

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The length of side B''C'' in polygon A''B''C''D'' = √((4 -3.5)² + (2 - 4)²) = (√17)/2

Also we have;

The length of side CD in polygon ABCD = √((6 -0)² + (-2 - (-2))²) = 6

The length of side C''D'' in polygon A''B''C''D'' = √((4 -1)² + (2 - 2)²) = 3

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The length of side DA in polygon ABCD = √((1 -0)² + (-6 - (-2))²) = √17

The length of side D''A'' in polygon A''B''C''D'' = √((1.5 -1)² + (4 - 2)²) = (√17)/2

Therefore the Polygon A B C D can be obtained from polygon A''B''C''D'' by multiplying each side of polygon A''B''C''D'' by 2

The correct option is therefore;

Use a scale factor of 2.

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2 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
Pls explain your work!
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Answer:

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Step-by-step explanation:

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Answer:

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