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NNADVOKAT [17]
2 years ago
6

Two teaching methods, A and B, are implemented for learning Spanish. There is a 70% chance of successfully learning Spanish if m

ethod A is used, and a 85% chance of success if methodB is used. However, method B is substantially more 3. time consuming and is therefore used only 20% of the time (method A is used the other 80% of the time). The following notations are suggested:
A-Method A is used.
B-Method B is used.
L-Spanish was learned successfully Interpret each of the probabilities given in the original problem in probability
a) notation with their respective values (four of these).
b) Draw a Probability Tree representing each of the probabilities mentioned above.
c) What is the likelihood a person does not learn Spanish?
d) A student learned the spanish successfully. What is the probability that they were taught by method B?

Mathematics
1 answer:
Mkey [24]2 years ago
3 0

Answer:

(a) Shown below.

(b) Shown below.

(c) The probability that a person does not learn Spanish is 0.18.

(d) The probability that method B was used given that a student learned the Spanish successfully is 0.83.

Step-by-step explanation:

(a)

Consider the provided data.

P(A)=0.20\\P(B)=0.80\\P(L|A)=0.70\\P(L|B)=0.85

Then the probability of not learning Spanish using the respective methods are:

P(L'|A)=1-P(L|A)=1-0.70=0.30\\\\P(L'|B)=1-P(L|B)=1-0.70=0.15

(b)

The Probability Tree representing each of the probabilities mentioned above is attached below.

(c)

Compute the probability that a person does not learn Spanish as follows:

P(L')=P(L'|A)P(A)+P(L'|B)P(B)

         =(0.30\times 0.20)+(0.15\times 0.80)\\\\=0.06+0.12\\\\=0.18

Thus, the probability that a person does not learn Spanish is 0.18.

(d)

Compute the probability that method B was used given that a student learned the Spanish successfully as follows:

P(B|L)=\frac{P(L|B)P(B)}{P(L|A)P(A)+P(L|B)P(B)}

            =\frac{(0.85\times 0.80)}{(0.70\times 0.20)+(0.85\times 0.80)}\\\\=\frac{0.68}{0.14+0.68}\\\\=0.82927\\\\\approx 0.83

Thus, the probability that method B was used given that a student learned the Spanish successfully is 0.83.

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A plane is flying at 1000 meters above the ground and fires a laser 60 degrees of of straight down. what is the distance the lig
juin [17]

Answer:

Step-by-step explanation:

The distance the light traveled to the ground is the range of the plane expressed as:

R = U*√2H/g

U is he velocity

H is the max height

g is the acc. due to gravity

Let us get U first using the formula

H = u²sin²Ф/2g

1000 = u²sin²60/2(9.81)

1000*19.62 = 0.8660u²

19620 = 0.8660u²

u² = 19620/0.8660

u² = 22655.88

u = √22655.88

u = 150.52m/s

Next is to get the range

R = 150.52√2(1000)/9.81

R = 150.52 √2000/9.81

R = 150.52√203.87

R = 150.52*14.28

R = 2149.16m

Hence the distance the light traveled to the ground is 2,149.16m

5 0
2 years ago
Rachel, Adam, Michelle, Hannah, and James are going to the movies. They have $65 to spend on tickets and snacks. Each movie tick
Ann [662]

Answer:

1. By substitution property of inequality

5(9.5)+4.5\leq65

2. By using multiplication  in equality then we get

47.5+4.5x\leq65

3. The five friends will have 3 snacks to split.

Step-by-step explanation:

Given

Five friends have total money= $65

Cost of each movie ticket= $9.50

Cost of each snack item= $4.50

Let ,five friends have total snacks = x

Total movie tickets=5

Because total number of friends=5

The inequality expressionis given by

I Step: 5(9.5)+4.5x\leq 65

Reason: By using substitution property of inequality

47.5+4.5x\leq 65[/tex2. Step :[tex]4.5x[tex]\leq65-47.5[/tex]

4.5x\leq 17.5  ( by subtarction 47.5  from both sides)

x\leq \frac{17.5}{4.5}   ( by dividing 4.5 on both sides )

<h3>x\leq 3.889  (by simplication)</h3><h3>x=3</h3>

Because they can buy maximum 3 snacks .

Beacause the number of snacks is natural number so we can't take in rational numbers.

<h3>Hence, the five friends will have 3 snacks to split.</h3>

6 0
2 years ago
Read 2 more answers
Solve the right triangle, ΔABC, for the missing sides and angle to the nearest tenth given angle B = 39° and side c = 13.
hram777 [196]

Answer:

Part 1) b=8.2\ units

Part 2) a=10.1\ units

Part 3) A=51\° and C=90\°

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

Find the side b

we know that

In the right triangle ABC

The function sine of angle B is equal to divide the opposite side angle B (AC) by the hypotenuse (AB)

sin(B)=AC/AB

we have

AB=c=13\ units

AC=b

B=39\°

substitute

sin(39\°)=b/13

solve for b

b=(13)sin(39\°)

b=8.2\ units

step 2

Find the side a

we know that

In the right triangle ABC

The function cosine of angle B is equal to divide the adjacent side angle B (BC) by the hypotenuse (AB)

cos(B)=BC/AB

we have

AB=c=13\ units

BC=a

B=39\°

substitute

cos(39\°)=a/13

solve for a

a=(13)cos(39\°)

a=10.1\ units

step 3

Find the measure of angle A

we know that

In the right triangle ABC

C=90\° ----> is a right angle

B=39\°

∠A+∠B=90° ------> by complementary angles

substitute the given value

A+39\°=90\°

A=90\°-39\°

A=51\°

5 0
2 years ago
RANDOMLY CHOOSING TWO POTENTIAL CLIENTS
gregori [183]
Let <span>Jacob, Carol, Geraldo, Meg, Earvin, Dora, Adam, and Sally be represented by the letters J, C, G, M, E, D, A, and S respectively. </span>

<span>In part IV we are asked:

</span><span>What is the sample space of the pairs of potential clients that could be chosen?
</span><span>
Since the Sample Space is the set of all possible outcomes, we need to make a set (a list) of all the possible pairs, which are as follows:

{(J, C), (J, G), (J, M), (J, E), (J, D), (J, A), (J, S)

          , </span>(C, G), (C, M), (C, E), (C, D), (C, A), (C, S)
<span>                   
</span>                      , (G, M), (G, E), (G, D), (G, A), (G, S)
<span>             
                                    ,</span>(M, E), (M, D), (M, A), (M, S)    
<span> 
                                               , </span>(E, D),  (E, A),  (E, S) <span>   
                                                          
                                                           , </span>(D, A), (D, S)
              
                                                                       , (A, S).}

We can check that the number of the elements of the sample space, n(S) is 

1+2+3+4+5+6+7=28.


This gives us the answer to the first question: <span>How many pairs of potential clients can be randomly chosen from the pool of eight candidates? 

(Answer: 28.)


II) </span><span>What is the probability of any particular pair being chosen?
</span>
The probability of a particular pair to be picked is 1/28, as there is only one way of choosing a particular pair, out of 28 possible pairs.

III) <span>What is the probability that the pair chosen is Jacob and Meg or Geraldo and Sally? 

The probability of choosing (J, M) or (G, S) is 2 out of 28, that is 1/14.


Answers:

I) 28
II) 1/28</span>≈0.0357
III) 1/14≈0.0714
IV)


{(J, C),  (J, G), (J, M),  (J, E),   (J, D),  (J, A),   (J, S)
          , (C, G), (C, M), (C, E),   (C, D), (C, A),  (C, S)
                      , (G, M), (G, E),  (G, D), (G, A),  (G, S)
                                   ,(M, E),  (M, D), (M, A),  (M, S)    
                                               , (E, D),  (E, A),  (E, S)    
                                                            , (D, A), (D, S)
                                                                        , (A, S).}
6 0
2 years ago
How many solutions exist for the given equation? StartFraction one-half left-parenthesis x plus 12 right-parenthesis equals 4 x
Firlakuza [10]

Answer:

One solution x = 2

Step-by-step explanation:

Given the equation:

\dfrac{1}{2}(x+12)=4x-1

Multiply this equation by 2:

2\cdot \dfrac{1}{2}(x+12)=2\cdot (4x-1)\\ \\x+12=2(4x-1)

Use distributive property:

x+12=8x-2

Combine the like terms:

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Thus, this equation has one solution x = 2

7 0
2 years ago
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