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BigorU [14]
2 years ago
12

The region bounded by the given curves is rotated about the specified axis. Find the volume V of the resulting solid by any meth

od. y = −x2 + 23x − 132, y = 0; about the y−axis
Mathematics
1 answer:
Julli [10]2 years ago
6 0

Answer:

V  = 23π/6

Step-by-step explanation:

V = 2π ∫ [a to b] (r * h) dx

y = −x² + 23x − 132

y = −(x² − 23x + 132)

y = −(x − 11) (x − 12)

Parabola intersects x-axis (line y = 0) at x = 11 and x = 12 ----> a = 11, b = 12

r = x

h = −x² + 23x − 132

V = 2π ∫ [11 to 12] x (−x² + 23x − 132) dx

V  = 23π/6

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Find the product. (a2)(2a3)(a2 – 8a + 9) 2a7 – 16a6 + 18a5 2a7 – 16a6 – 18a5 2a8 – 16a7 + 18a6 2a12 – 16a7 + 18a6 consider the d
Fofino [41]

Answer: 2x^7 -16a^6 +18a^5


Step-by-step explanation: Given expression (a^2)(2a^3)(a^2-8a + 9).

The first factor (a^2) has a degree of : 2 because power of a is 2.

The second factor (2a^3) has a degree of : 3 because power of a is 3.

The third factor (a^2-8a + 9) has a degree of : 2 because highest power of a is 2.

Let us multiply them now:

(a^2)(2a^3)(a^2-8a + 9).

First we would multiply (a^2)(2a^3).

According to product rule of exponents, we would add the powers of a.

Therefore,

(a^2)(2a^3) = 2a^{2+3}= 2a^5

Now, we need to distribute 2a^5 over (a^2-8a + 9)

Therefore,

(2a^5)(a^2-8a + 9)= 2a^{5+2} -16a^{5+1}+18a^5

=2x^7 -16a^6 +18a^5

Highest power of resulting polynomial 2x^7 -16a^6 +18a^5 is 7.

Therefore, The product has a degree of 7.

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2 years ago
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The average score of all golfers for a particular course has a mean of 64 and a standard deviation of 3. Suppose 36 golfers play
kondaur [170]

Answer:

the probability that the exceeded 65 = 0.3707

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Step-by-step explanation:

<u>Step 1</u>:-

The average score of all golfers for a particular course has a mean of 64 and a standard deviation of 3.

mean (μ) = 64

standard deviation (σ) =3

by using normal distribution

given (μ) = 64 and  (σ) =3

i) when x =65

z = \frac{x-mean}{S.D} = \frac{65-64}{3} = 0.33 >0

P( X≥ 65) = P(z≥0.33)

              = 0.5 - A(z₁)

              = 0.5 - 0.1293 (see normal table)

             = 0.3707

The average score of the 36 golfers exceeded 65

                        = 36 X 0.3707 = 13.3452

                                               

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6 0
2 years ago
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