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Vlada [557]
2 years ago
4

What is the length of Line segment M N? 58cm 75cm 88cm 116cm

Mathematics
1 answer:
Ugo [173]2 years ago
4 0

Answer:

58

Step-by-step explanation:

use equations to get answers

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If m∠1 = 50, then m∠5 =
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2. angle 1 and angle 5 are corresponding angles [Given]
3..Therefore angle1=angle 5 [ Corresponding angles are =]
4..Therefore angle 5 = 50 degrees [= angles have same measure]

The above assumes that we are talking about corresponding angles of congruent or similar polygons or corresponding angles forme when a transversal intersects two parallel lines
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Using the chart "Amount of $1 at Compound Interest" from previous reading section "More Compound Interest", find the total amoun
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Annually:    Total Amount= $1,611.76   Interest Amount= $711.76

Semiannually: Total Amount= $1,625.50  Interest Amount= $725.50

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Four brothers each bought two hotdogs and a bag of chips at the concession stand.if the bag of chips was $1.25,and the total was
ahrayia [7]

Answer:

  $1.65

Step-by-step explanation:

The total purchase can be described by ...

  4(2h +1.25) = 18.20 . . . . where h is the price of a hot dog

  8h = 13.20 . . . . . . . . . . . subtract 5.00

  h = 1.65 . . . . . divide by 8

The price of a hot dog was $1.65.

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Brett plays an acoustic guitar at an event for $500. At the end of the event, the sponsor tips him 20%. How much does Brett make
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Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian
777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\B=30^o

Applying the law of sines

Find the measure of angle A

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(A)}=\frac{2}{sin(30^o)}

sin(A)=1

so

A=90^o

Find the measure of angle C

In a right triangle

we know that

B+C=90^o ----> by complementary angles

B=30^o

therefore

C=60^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{b}{sin(B)}

substitute the given values

\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}

c=2\sqrt{3}\ units

therefore

The dimensions of the triangle are

A=90^o

B=30^o

C=60^o

a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units

<em>Second case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\A=30^o

Applying the law of sines

Find the measure of angle B

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(30^o)}=\frac{2}{sin(B)}

sin(B)=0.25

so

using a calculator

B=14.48^o

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

A+B+C=180^o

A=30^o\\B=14.48^o

therefore

30^o+14.48^o+C=180^o

C=135.52^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{a}{sin(A)}

substitute the given values

\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}

c=5.61\ units

therefore

The dimensions of the triangle are

A=30^o

B=14.48^o

C=135.52^o

a=4\ units\\b=2\ units\\c=5.61\ units

see the attached figure to better understand the problem

4 0
2 years ago
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